Rudolph The STEM Nose Reindeer?!

[@marioprogamer12345]

bro 10ms^(-2) acceleration for 8km 💀 poor rudolph :(

[@its_puggy_pugster8469]

Wow, what a spectacularly festive way to learn some math, I didn’t even know you could calculate work! Work it Nicholas! 😜

[@hannesniklasson3888]

This assumes a coefficient of friction of 1, which is very unrealistic. Blindly plugging things into formulas will not always yield the right answer.

[@TheGuy-uk1cw]

The problem specifically states that there is no friction, but that would not have mattered. Newtons second law states that the SUM of all forces are equal to a*m. This means that even if we were including friction (or any other resistance for that matter) we would still get the right amount of work using this method, as long as the acceleration is constant.

[@miracletraveler2835]

Bros too lost to realize a coefficient of 1 will make the sleigh completely unable to move anywhere

[@user-dq7jo4fn9y]

Theyre too easy trick us

[@GOVTEXAMAspirant-h7h]

Literally wrong calculation, W=F×S×cosA, now there is no friction which means there is no force apart from its weight but the angle A =90° , so work is Literally 0

[@Bcs952]

You can’t do work in space?

[@tacomiester]

The cos is pointless on a flat surface and the angle of it is 0 not 90 since it’s cos(angle from the horizon) aka cos(0) which is equal to 1

[@Ninja20704]

No, you are completely wrong here. A is 0 degrees here, so cosA is 1. The angle A is the angle between the pulling force by the reindeer and the displacement vector. The weight of the sleigh has nothing to do here

[@GOVTEXAMAspirant-h7h]

​@Bcs952 not unless you are accelerating or going against gravity

[@GOVTEXAMAspirant-h7h]

​@Ninja20704 nope you are wrong , no where in the problem acceleration or time is mentioned I will assume the deer was moving at a constant speed . Now the only force he is working against is at 90° from its vector so w=0