Factoring sum of squares | Imaginary and complex numbers | Precalculus | Khan Academy

[@liffidmonky1216]

and for what kind of problems can u use this trick?

[@14Anon2]

The problems you see in this video. It saves time.

[@pearlstar1427]

Just in case anyone like was wondering like me why i^2.y^2 is not (i.y)^(2+2), the reason is because that would only be true if i and y were the same.

[@BLACKED.commercial]

Yes. i²y² = (i₁ * i₂) * (y₁ * y₂) (iy)² = (iy)₁ * (iy)₂ There are two factors of i and two factors of y in each expression. The only difference is the order of multiplication. But order doesn't matter in this context, as allowed by the commutative property of multiplication. The distribution (or factoring) of exponents is the reordering of the factors.

[@patricioparga9580]

Nice! I had forgotten how to do this :P Need a little refresher

[@Floezy]

hello from 2020

[@peteruiz5948]

Great video.

[@alicialexists]

So cool.

[@Leoooooooo13]

What would you do if you had something like x squared + 25

[@polobobeetricethe3rd567]

(x + 5i)(x - 5i)

[@Leoooooooo13]

@@polobobeetricethe3rd567 ty

[@abhigyanshukla]

Can it be simply written as a^2 + b^2 = (a+b)^2 - 2ab

[@Arthursk-zb3nj]

You can but if the equation is set to 0 it is easier to work with a multiplication

[@ngndnd]

Bruh so im practicing on khan academy and it would have been more helpful if u included harder questions. The questions they gave me on the website were nothing like this one.

[@abhissmalizard8732]

Why does he drop a negative sign in the start of the video?

[@conpa18dany]

In the realm of infinity, wouldn't i^2 be a contradiction to omega?

[@Floezy]

tryhard!!!