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From the TISE in 3d to spherical harmonics

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Brant Carlson

Brant Carlson

Күн бұрын

Separation of variables applied to the time independent Schrodinger equation gives an angular equation with spherical harmonic solutions. (This lecture is part of a series for a course based on Griffiths' Introduction to Quantum Mechanics. The Full playlist is at www.youtube.com...)

Пікірлер: 64
@DodoEmperor
@DodoEmperor 7 жыл бұрын
I started today with a quantum intro course starting here. I got freaked out by this griffiths chapter. Some friend of mine recommended this to me but you solved essentially most questions that I had and in hindsight you made me understand previous parts better. Thanks man, it's very clear. Even clearer than griffiths himself and he is very clear
@PankajBhambhani64
@PankajBhambhani64 4 жыл бұрын
These videos are really Legendre-ary! Thank you for sharing these videos.
@dbf72829
@dbf72829 Жыл бұрын
😭🤣
@MiguelGarcia-zx1qj
@MiguelGarcia-zx1qj 3 жыл бұрын
38:25 an easier to read depiction of spherical harmonics can be obtained by using saturation instead of value of light for the magnitude of the functions. So, the highest magnitudes would be represented as fully saturated colours, and low magnitudes would appear as mostly white (instead of black). I devised such a scheme, around 23 years ago, in order to represent said harmonics upon a sphere.
@MarioRiveraS96
@MarioRiveraS96 7 жыл бұрын
Thanks! You might have just saved my quantum mechanics course with this video!
@jacobvandijk6525
@jacobvandijk6525 Жыл бұрын
And what have you done with it?
@GammaDigamma
@GammaDigamma 4 жыл бұрын
m and l are actually the quantum numbers where m is the magnetic quantum number giving the number of degenerate orbitals and l is the azimuthal quantum number giving which subshell were talking about (s, p, d or f)
@iqranasir9224
@iqranasir9224 2 жыл бұрын
thank you for saving my semister 😍
@KingCrocoduck
@KingCrocoduck 9 жыл бұрын
Mistake at 14:17 the r^2 term should have cancelled out
@KingCrocoduck
@KingCrocoduck 9 жыл бұрын
nevertheless this video kicked ass
@MisterTutor2010
@MisterTutor2010 9 жыл бұрын
King Crocoduck perhaps you can do a video giving a foul mouth explanation of the rigid rotator as you did with the harmonic oscillator :)
@matthewlemke5310
@matthewlemke5310 4 жыл бұрын
@@MisterTutor2010 4 years ago you were triggered.
@MisterTutor2010
@MisterTutor2010 4 жыл бұрын
@@matthewlemke5310 What are you talking about? That video was hilarious.
@ifrazali3052
@ifrazali3052 Ай бұрын
​@@matthewlemke53109 years ago lol How are you guys holding up?
@santosfuentes1519
@santosfuentes1519 9 жыл бұрын
question: at 15:03 after you have divided out (- hbar squared RY over 2 m r squared) shouldn't r squared be canceled out? should you not have (1/R)dr(r^2dR) ? thanks!
@navneetmishra3208
@navneetmishra3208 3 жыл бұрын
Yup
@kgfcccvvhbbbc7565
@kgfcccvvhbbbc7565 2 жыл бұрын
@@navneetmishra3208 yes. No r squared. Teacher forget r squared. I forgive you.
@cosmicnomad8575
@cosmicnomad8575 2 жыл бұрын
That was excellent! Well done! Such a beautiful concept in my opinion!
@clopensets6104
@clopensets6104 4 жыл бұрын
I have been having trouble grasping the concept of spherical harmonics for days!!! My textbook didn't help in clarifying the mathematical details, as it mainly focused on the physical and experimental implications of mathematically predicted 'orbital configurations' (which were derived via spherical harmonics). This video helped clarify a lot of the mathematical components, which I was too lazy to research myself. THANKYOU FOR YOUR INSIGHTS!!
@SlySkills
@SlySkills 5 жыл бұрын
Answers to your questions either in your video description or as a comment is the only thing these videos are missing to really check our understanding. Thank you so much for everything though. You've done more than enough and it's greatly appreciated.
@SlySkills
@SlySkills 5 жыл бұрын
Attempted Answers: Find P(1,1) (cos(theta)) = sin(theta) P(7) = 0 at 7 different points P(4,7) = 0 at 3 different points - This one is pretty much a guess, not sure how to compute. m = -3 then l = 3, only allowed value
@BPHSadayappanAlagappan
@BPHSadayappanAlagappan 2 жыл бұрын
Awesome 😎
@BPHSadayappanAlagappan
@BPHSadayappanAlagappan 2 жыл бұрын
I think if M=-3, L can be greater than 3.
@briannagopaul3493
@briannagopaul3493 3 ай бұрын
Thank you for these lectures, these make so much more sense!!
@paladin1147
@paladin1147 4 ай бұрын
Amazing, just check the comments for certain errors or keep the Griffiths book next to you to verify. Thank you for the video
@erikstephens6370
@erikstephens6370 2 жыл бұрын
14:17 that term should be 1/R, not 1/Rr^2. The r's from the Y/r^2 and -h^2/2mr^2 cancel each other. Still, a great video.
@mojamamaduda
@mojamamaduda 8 жыл бұрын
thanks for this video,you are a legend
@ameerbux78666
@ameerbux78666 4 жыл бұрын
wow, only thing sad here is that ive only dicoverered this channel now. thanks for the vid, you explain great
@dm3248
@dm3248 4 жыл бұрын
Thanks for such an amazing lecture..!!
@scitwi9164
@scitwi9164 7 жыл бұрын
09:00 Are you sure about that? If the X part is a constant, then they Y+Z part is equal to the same constant with a negative sign. But X and Y can still change in various ways, just independent of x, right?
@clopensets6104
@clopensets6104 4 жыл бұрын
What do you mean? The 2nd derivative of X multiplied by the inverse of X, is only equal to the negative of the sum of the 2nd derivatives of Y and Z respectively, each multiplied by their respective inverses, when the potential energy equals the energy eigenvalue.
@bakirev
@bakirev 4 жыл бұрын
I didn't quite get the reasoning of spherical coordinates not being independent of each other which causes the laplacian to be complicated. It was that vector r changes if you change phi for example. But r is just the distance right not the vector?
@rebekahshtayfman1967
@rebekahshtayfman1967 7 жыл бұрын
I think you meant r^2*sin(theta)*dr*d(theta)*d(phi) at the 38 minute mark (approximately) By the way, thank you for the amazing videos. You're great!
@takinyele
@takinyele 8 жыл бұрын
Oh my god I love you so much
@user-fv6lb1xx7f
@user-fv6lb1xx7f 4 жыл бұрын
Thanks 💜
@Al-Qaisi_Iraqi
@Al-Qaisi_Iraqi 26 күн бұрын
Thank you
@rajupdl6
@rajupdl6 4 жыл бұрын
Awesome lecture 👍
@user-ye7gg2xl5q
@user-ye7gg2xl5q 8 жыл бұрын
thank you
@wonka5004
@wonka5004 7 жыл бұрын
Great explanation 10/10
@BLVGamingY
@BLVGamingY 6 ай бұрын
why isn't at 22:30 the phi function an arbitrary sum of opposite exponentials as opposed to just one exponential nonetheless m ends up a whole number
@seacaptain72
@seacaptain72 6 жыл бұрын
Is there somewhere I can find the solutions to the check your understanding questions at the end? I've done these on all the vids but haven't been able to check them
@navneetmishra3208
@navneetmishra3208 3 жыл бұрын
THANK YOU SO SO MUCH
@learningwithsaba6131
@learningwithsaba6131 5 жыл бұрын
superb
@ZeroXAlAttas
@ZeroXAlAttas 9 жыл бұрын
Wow, this really helps~~ thanks!! :))
@clopensets6104
@clopensets6104 4 жыл бұрын
In 36:10 . Just out of curiosity, how do you get the normalisation factor from evaluating the double-integral underneath???
@movintarget300
@movintarget300 4 жыл бұрын
It's the same as the normalisation integral for more familiar Cartesian coordinates, except we are now in spherical polar coordinates, so dxdydz -> r^2sin(theta)d(theta)d(phi)d(r). I think you can just grind through this by plugging in (Y*Y) . This may be done in more detail in Griffiths Intro or try googling Jain QM pdf and it's done in there.
@hasnatahmad6164
@hasnatahmad6164 4 жыл бұрын
one thing I didn't understand what are "pheeta" and "phi" here
@movintarget300
@movintarget300 4 жыл бұрын
Solutions of the wavefunction in spherical polar coordinates split into the dependence on pheeeta and phii. Edit: you can also solve for the r dependence but is less important in angular momentum which is... well, angular.
@inperatieloos
@inperatieloos 8 жыл бұрын
37:58 isn't it r^2*dr*sin([T])d[T]*d[F]?
@rap8209
@rap8209 8 жыл бұрын
+inperatieloos I think d(Omega)=Sin(T)d(T)d(Phi) so here he integrated over omega, not considering radial part
@fcmilsweeper9
@fcmilsweeper9 9 жыл бұрын
Wait why do they have to be constant?
@Prometheus4096
@Prometheus4096 9 жыл бұрын
+fcmilsweeper9 Without context, I think in the case you think about both describe the energy of the same system.
@Salmanul_
@Salmanul_ 4 жыл бұрын
Why spherical coordinates?
@HankGussman
@HankGussman 3 жыл бұрын
Orbitals can be described in terms of spherical coordinates.
@jacobvandijk6525
@jacobvandijk6525 Жыл бұрын
Why do you describe your room with Cartesian coordinates? Because it is rectangular. Why do we describe the "room" of an electron with spherical coordinate? Because it is spherical (most of the time), they think.
@knowledgebankforfpscppscnt5486
@knowledgebankforfpscppscnt5486 4 жыл бұрын
22:18 how
@alexkumarsingh2805
@alexkumarsingh2805 4 жыл бұрын
29:11 0
@movintarget300
@movintarget300 4 жыл бұрын
Plot out cos(x) for 0 cos(pi)=-1.
@alexkumarsingh2805
@alexkumarsingh2805 4 жыл бұрын
Thank you
@herman9737
@herman9737 4 жыл бұрын
why cant weee just stick to cartesian.... jk spherical reveals nice intrinsic proterties of QM
@craigfowler7098
@craigfowler7098 4 жыл бұрын
My brain hurts
@Salmanul_
@Salmanul_ 3 жыл бұрын
28:31, fractional derivatives exist so idk about that.
@shayanmoosavi9139
@shayanmoosavi9139 3 жыл бұрын
If m is not an integer the phi dependence of the wave function won't be single valued and our boundary condition which is Φ(0)=Φ(2π) won't be satisfied. Also fractional derivatives are extremely advanced stuff. This is an *introduction* to quantum mechanics which is for undergraduates. I've found this article, I hope it answers your question : en.m.wikipedia.org/wiki/Fractional_Schr%C3%B6dinger_equation Although I haven't understood a single word😂😂
@MinuteMayne
@MinuteMayne 5 жыл бұрын
Bruh the way you write partials is wildly distracting.
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