WOAH! I wish you where my professor! You explain things so thoroughly it makes so much sense.
@Hunar19977 жыл бұрын
Neil Volk Our professor gave this as a homework .. this video was my savior
@williamnelson496810 жыл бұрын
What an excellent series of minilectures! My probability density curve for grokking QM integrated over all of your videos is equal to one (understanding!) thanks to your insightful presentations.
@matrixate4 жыл бұрын
I envy your students Dr. Calson. I wish that my University had you in their Physics Department. I've learned so much from just your videos alone.
@iknowthatdubin48774 жыл бұрын
Great lecture for self independent learners!
@mikebeard35248 жыл бұрын
Thank you for your clear explanations. I think you are a great teacher.
@edisonlin17769 жыл бұрын
At around 12:15, you explain that the equation f(t) = g(x) must hold for every t and every x. Could you explain why that must be the case? Thanks!
@faielgila73753 жыл бұрын
That relationship came from simplifying the original differential equation, so if that equality is false then X(x)•T(t) would not be a solution to the differential equation (Six years ago, hopefully this is still relevant for you 😅)
@pedramnoohi27153 жыл бұрын
@@faielgila7375 hopefully he hasnt bene stuck on this for 6 years lol
@captainhd97413 жыл бұрын
@@pedramnoohi2715 or dead
@Oh4Chrissake7 жыл бұрын
Lovely insight into the wave equation being a relationship between acceleration and curvature.
@jozokukavica98146 жыл бұрын
Yeah. That point really is a lovely idea.
@stephanie87649 жыл бұрын
What a fantastic video!! Thanks a lot!
@alessiajacquard5 жыл бұрын
I understand many concepts with you :D I wish that you share more videos about undergraduate physics like 'electromagnetic theory' :)
@scitwi91647 жыл бұрын
25:30 So this is basically an *eigenvalue problem* for the differential operator :J The eigenfunction of the differential operator is the exponential function, and the eigenvalue is -i·E/ℏ, or from de Broglie's equation E = h·f = ℏ·ω → E/ℏ = ω we get that the eigenvalue has a form -i·ω .
@jimdogma153711 жыл бұрын
Very cool and insightful video. Looking forward to the rest. Thanks.
@aljosagraovac191811 жыл бұрын
excellently explained and simplified
@brendansmith6708 жыл бұрын
Amazing videos! Very clear.
@alpineblob7 жыл бұрын
I needed this video. Thank you!
@jamieluskin16638 жыл бұрын
this is fantastic and so clear thank you!
@AkshitSharma02 жыл бұрын
Sir you are just amazingg, thank you so much!
@elias199 жыл бұрын
If the schrodinger equation comes from he classical wave equation, why in the first term in the time dependent schrodinger equation appears the psi function in the first derivative and not in the second derivative form? Hope i make miself clear, im not that good at english. thanks
@scitwi91647 жыл бұрын
It's because the Schrödinger's equation has been derived by taking the formula for the wave function of a "free particle" (plane wave) and replacing the ω and k with E/ℏ and p/ℏ, and then looking for the time and space derivatives, which are needed for the Hamiltonian. The wave equation is not a Hamiltonian - it expresses the dependence between the curvature in space and the curvature in time of the wave function, which are both second-order derivatives. The Schrödinger's equation, on the other hand, expresses the dependence between the kinetic energy (related to changes in time) and the potential energy (related to changes in space), which are first-order derivatives. There's a nice analogy you can take a look at, regarding harmonic motion: The equation for the Simple Harmonic Oscillator (SHO) i s d²x/dt² = -ω²·x, so it is has a second-order derivative, and the solution is that nice sinusoidal oscillation you're probably well familiar with. But the harmonic oscillator can be also expressed in the Hamiltonian way, in terms of energies: the total energy E consists of kinetic energy m·v²/2 and potential energy k·x²/2, so the Hamiltonian is E = m·v²/2 + k·x²/2. Now you can replace the `v` in this formula by the first derivative of position with respect to time, dx/dt, obtaining: E = m·(dx/dt)²/2 + k·x²/2 It is just a different way to express the conditions on the function which describes the motion of the oscillator: one is in terms of curvatures, the other is in terms of energies. But the solution is the same for both, because they both describe the same harmonic oscillator.
@m.huzaifam.siddique80166 жыл бұрын
thanks. You are a good teacher
@armelivanbado20465 жыл бұрын
You are the best!
@abdulwilliamgokul2486 Жыл бұрын
Excellent sir
@ILsupereroe672 жыл бұрын
At 24:36 how do you know E is real and not complex?
@Andrew6James5 жыл бұрын
Can someone explain why both solutions to the 2nd Order ODE was not included. Should we not get the solution T = Aexp[-sqroot(a)t] + Bexp[sqroot(a)t]? Why has the negative one been ignored?
@tis_i_sana2 жыл бұрын
No! The ODE has been solved by rearranging the variables and integrating, it is not a seond order ODE with the general solution of Aexp[-wt] + Bexp[wt]
@moussamancer8014 жыл бұрын
hi mister and for the solution of the shrodinger equation in polar cordinates by separation of variables ?
@mohammedtalibmosa73448 жыл бұрын
thank you so much sir
@sunnypala96946 жыл бұрын
Sr great explaination
@scitwi91647 жыл бұрын
Hmm so what is it that makes an equation separable? How can we tell if a given equation can be solved by separation of variables or not before actually trying? (since the separation process can be messy sometimes, and it would be cool if we could tell if it will work before going into all those gory details :q )
@alcoll10387 жыл бұрын
Sci Twi I've been wondering myself. From what I can gather (also from the book), if there is another function in the PDE that makes it so that the variables can't be seperated easily, solving the PDE will become a whole lot harder. The example they gave was if V was V(x,t) instead of just V(x), then it will not be possible to solve with SOV if V's variables aren't seperable themselves...? I don't know. Maybe there exists some weird PDE that has has the exact opposite property.
@debasishraychawdhuri3 жыл бұрын
Can V depend on time? Can solve the equation then?