How To Analysis and Design Water Tank In ETABS & SAFE 2023

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Mr EngineerO

Mr EngineerO

Күн бұрын

Пікірлер: 18
@smokelm35
@smokelm35 9 ай бұрын
good job what if we use 0.35 modifier from begin
@RD-gj4ki
@RD-gj4ki Ай бұрын
DID YOu consider the weight of the walls on the when designing the slab in SAFE?
@MrEngineerO
@MrEngineerO Ай бұрын
Thank you for watching structural walls weight are considered in etabs
@vasubhadania
@vasubhadania 9 ай бұрын
Can you please make a video on design of staircase.... Modeling is possible I want to know if design of staircase is possible......
@Johnny_Nelson
@Johnny_Nelson 5 ай бұрын
Can it be defined "joint patterns" in ETABS?, for instance dynamic water load
@MrEngineerO
@MrEngineerO 5 ай бұрын
joint patterns exist only in sap2000
@syedarsalanali8506
@syedarsalanali8506 11 ай бұрын
Instead of music.. You can explain the working..
@mohab96
@mohab96 8 ай бұрын
Why did you not add rebar ?
@Amla09
@Amla09 4 ай бұрын
Can't you make the foundation in etabs also?
@MrEngineerO
@MrEngineerO 4 ай бұрын
Yes it can be done Please watch my other tutorials about structure with foundation design with this link kzbin.info/www/bejne/ZomXi56mp8-apNU
@M.Lozano
@M.Lozano 3 ай бұрын
6:07 POR QUE MODIFICA CON ESOS FACTORES?
@carlosmolinatorres9967
@carlosmolinatorres9967 2 ай бұрын
Eso dice la norma el ACI son factores de reducción de rigidez. Hay 0.70 para muros no agrietados y 0.35 para muros agrietados
@abd-allahessam7598
@abd-allahessam7598 11 ай бұрын
3 x 4.7 x 2 = 28.2 not 12.40
@MrEngineerO
@MrEngineerO 11 ай бұрын
Thank you for your attention
@ahmedkamal7738
@ahmedkamal7738 7 ай бұрын
Brother it is wrong to design water tank wall by etabs because pier force do not consider horizental moments
@engamirsamyfaragalla4726
@engamirsamyfaragalla4726 7 ай бұрын
Fr=1.9 *lampa*sqrt Fc AS PER CODE NAME ?? ACI CODE Fr=0.62 LAMPA SQRT FC
@MrEngineerO
@MrEngineerO 7 ай бұрын
Dear engineer, thank you for your attention. fr in ACI is based on PSI and can be converted to kgf/cm2 as follows: fr=7.5√f'c in PSI=7.5(0.070307*(√(f'c/0.070307)))=1.9√f'c in kgf/cm2
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