Inert and Labile Complexes | Easiest Explanation

This is very Important video for understanding Outer and Inner Sphere Electron Transfer Mechanism.
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#labile #inert #coordination

[@rekhasehgal9769]

That's called explained in short time without any nonsense talk 👍

[@sangeetachingangbam7286]

Sir, your videos are very well explained with basic concepts and I loved it. I was having lots of confusion but after watching your videos my doubts are all cleared now.

[@kirtikumar683]

Sir , u have made the concepts so clear. Thanks alot.

[@priyankabansal9980]

Thousands of like to this video...ur explanation is appreciable and more than awsm..

[@udayshankar3817]

Sir it is really helping you have generated concept for me regarding inert and lebile chemistry ... sir while reading through book i find d7 d9 are inert for low spin complex.

[@himansarma5587]

Sir your videos are Helping me a lot... Thank You so much..

[@aadilyaseen733]

Thanks sir..Ur videos really give boost to our preparation of CSIR NET exam...With love from Kashmir.

[@AllBoutChemistry]

Thank you 😇 Best wishes from my side.

[@ibrahimfayazlive2277]

D8 configuration is Inert. Due to symmetry and CFSE Value equal to . HS. -2.00 and LS. -2.00. Experience, see Ajai Kumar he had mentioned this energy is required thus becomes inert

[@FreeRadical23]

Ryt d8 in inert

[@akulaumesh3735]

Sir, I am pursuing MSc chemistry first year at Ananthapuram arts college,I learnt lot of chemistry from ur videos

[@lordshiva314]

really sir all concept 👌 👌 is well.god bless you sir...

[@susmiraja]

Awesome explanation sir... Thanks much

[@nalinatg6343]

thanks a lot for making concepts easier to understand ,,,thank u sir

[@AllBoutChemistry]

You're welcome 😇

[@sdjyothirmayi8326]

Nice explanation.. Tq.. Ur explanation is awesome

[@vijayalakshmit9230]

Love your videos. Thank u

[@suryav3039]

Really useful video....thank you sir

[@gopalkrishnaniyogi5941]

Sir d4(ls) is labile? d8 is inert?It is exceptional case.Tell me about it sir.

[@avanisingh2525]

Sir if it is a high spin complex if it is in the influence of weak ligands then pairing should take place in t2g orbitals first why eg orbitals are get paired before t2g in octahedral complexes in CFT

[@avanisingh2525]

Sir in sp3d2 hybridised complex dz2 orbital is vacant and until it is fully filled we can't prefer further orbitals. I have this confusion, kindly me help me out with this🙏🙏. Thankyou 🙏

[@aqibbajaj3135]

If possible please make a video on rate of exchange.... Explaination along with questions

[@rashmishukla6864]

I love thz vedio...thankyu so much sir..& sir plz 4 month ke bad csir net exam h so plz keep uploading more n more vedios by series....😊😊

[@AllBoutChemistry]

I'll try to make atleast 2 videos per week. Taking out time for videos alongwith research work is little difficult. But I'll try to make videos regularly

[@rashmishukla6864]

Yes sir..I can understand :) well..best off luck with my best wishes for ur research work :))😊

[@AllBoutChemistry]

Rashmi Shukla Thank you 😇

[@rishadadwal5690]

Very nice sir....mne apka channel dekhna randomly shuru Kia or ab m apke teaching skills ki fan ho gyi ho...keep going sir 🌸

[@AllBoutChemistry]

Thank you 😊😊

[@ershanaoc4264]

Tank you for your valuable class sir

[@vlogwithif3618]

Thank you and love you

[@shubhamjaiswal2282]

sir thankyou very much for the videos . happy teachers day.

[@AllBoutChemistry]

thank you dear :)

[@pushpendubaidya_honest_talk]

Best teacher in the world

[@guntinarahari3031]

For chemistry

[@selvanmeil5197]

Thank u sir for teaching in English

[@TheSanathanWorld]

Bro u can create a what's app group.

[@leenaanil5989]

Sir d0, d1 and d2, they don't have eg electrons ,then how it become labile and d3 become inert.

[@chemikamesh4788]

one doubt in that, we find that, this complexes are high spin or low spin get confused... So its easy way to find that strong field ligands are low spin complex and weak field ligands are high spin complexes.....These are said by my faculty its correct or not

[@gomathit1560]

so nice sir.thank you sir

[@praveenkannanspk7570]

D1,d2,d0 also have no repulsion eg0 according to concept it also has no repulsion means inert only know

[@sasmitasenapati9702]

What is the meaning of higher in energy and lower in energy according to VBT.... I can't understand... Plz any one reply.

[@dipikasharma630]

sir can u plz provide a video lecture of bio inorganic for csir

[@artidabas2432]

But in (Cr (CN)6)3- pairing will be occur because CN is strong ligand So plzz tell how it is possible or the reason of this

[@alkakalia5795]

Very nice explanation 😊

[@sudheer2643]

Thank you very much sir

[@monishadas2970]

Why d0, d1 ,d2 are labile as you explained sir while they have vacant eg ?? But according to CFT they should be inert in nature as you said sir in this video !! Kindly explain plz sir

[@sasi8217]

Leave this question as choice..

[@gowtamkumar2537]

one orbital (dz^2) is empty in mn+3 why it doesn"t allow cl to occupy

[@hitarthsoni6042]

Thank you sir. 🙏

[@shivanitripathi7407]

sir, are these videos of coordination playlist is enough to study for coordination unit for csir-net.

[@farooaqinetwork4268]

Where from you

[@amolpahune5993]

[Cr (H2O)6]3+ and [Mn(H2O)6]3+ is labile or inert please help

[@user-bq5nv9zh8p]

TQ so much sir❤️

[@EMNeranjanaVarrsha]

Thank you sir ❤️

[@rupaligutte9789]

Thank you 😊

[@ayushirangari6390]

Thank youu ❤😊

[@ramlathshaikh9943]

Nice explanation

[@gollavineetha3482]

sir,continue the videos,only few days left for Ap research set exam

[@AllBoutChemistry]

It's difficult for me to make videos daily. I have lab work also, so plz cooperate. I am trying to provide two videos per week

[@bhargabbiswas1134]

d8 is inert no ? As cfse of its low and high spin is always -ve .

[@ychemistry2613]

thanku so much sir

[@sachirai7942]

You are great 👍👍🔥🙏🙏💥💢 sir

[@sivarajn1930]

Thank you g

[@chemikamesh4788]

tnq sir....i am waiting for more and more videos..

[@AllBoutChemistry]

Hi Kamesh, you can join me on Unacademy, there I'm posting more videos 👍

[@chemikamesh4788]

Already i joined

[@aryansonu2440]

A+++++++ Videos dear sir

[@bhagavanchowdary2303]

Sir small doubt 7:55 in 3d orbit one orbital is vacant, but why not fill that orbital (mn3+)

[@knowingchemistry735]

Because hybridisation main outer d orbitals involved hai therefore that only taking part in bonding thus electrons are filled in them leaving inner 3d orbital vacant. I hope it helps..

[@rashmishukla6864]

Osm vedio :) Sir plz upload for stereochemistry...🙏🙏

[@AllBoutChemistry]

Stereochemistry I'll upload on Unacademy. Plz follow me. There

[@Boopathi_Kittusamy86]

In outer orbital complexes at 3d orbital, only 4 electrons are filled one orbital vacant why ?? 6 chlorine electrons not filled by that vacant 3d orbital.. can u explain

[@bhagavanchowdary2303]

Boopathi Kittusamy bro same doubt

[@aarushikandari8963]

Same doubt

[@muneerhussaindar]

Due to oxidation state.

[@gowtamkumar2537]

in case of [cr(CN)6]-3 complex CN is strong ligand so the electrons are filled against hunds rule but you filled sigle electrons in 3dxy',3dyz,3dzx, why

[@rupeshkumar-lh3xz]

Tank u sirr

[@vijaysagar1001]

Plz explain Hard acid, hard base & saft acid, saft base concepts

[@AllBoutChemistry]

Ohhkkk brother

[@Zul_qar_nayn_]

Thermodynamic stability is measure how much tendency reactant have to lower energy when it form product.

[@nirmalarawat7780]

Thankyou

[@kishnamandal6798]

Bro explain hydration energy & lattice energy in coordination complex

[@AllBoutChemistry]

Alright bro... I'll make on this very soon, 👍

[@abdullahbukhari9779]

Best video

[@gopalkrishnaniyogi5941]

Plz answer this question sir.

[@vidhya5380]

Tq sir

[@maheshtumkurmaheshkp3903]

nice sir

[@netchem6322]

thank you sir

[@AllBoutChemistry]

You're welcome 😇

[@Nandan97]

achchha hai..

[@srikrishnasharma1425]

14:47 u said if electrons are in eg then they are labile. 15:02 But in case of d1, d2, d3 there is no electron in eg still they are labile. Didn't explained well. Give the reason. Please explain it .

[@ankita1434]

Same problem

[@ankita1434]

Sir please explain this

[@OmarMohamed-kv3pj]

I think because there is empty place in the d orbital so a ligand can make associative reaction and put its lone pair in any place from the empty places i think it is according to valence bond theory

[@Zul_qar_nayn_]

Kinetic stability is how fast reaction proceeds if fast then kinetically unstable if slow then kinetically stable it give Idea about activation energy less activation energy means complex is kinetically unstable and.....

[@snehlatakatheria7212]

👍👍👍👍

[@soumyamuttagi]

I follow you on unacademy :)

[@farooaqinetwork4268]

Best

[@farooaqinetwork4268]

Where from you

[@kishoryadav9976]

Sir d8 are inert.

[@tamilnews2479]

❤

[@chemikamesh4788]

nice

[@anubovas7740]

Sir, d8 is inert right?

[@organiclovers6432]

Yup

[@OmarMohamed-kv3pj]

But d8 is inert i think because there is no octahedral distortion

[@prabhchemistrytips803]

👌👌👌👌👌

[@chemistrywidbikash6934]

Sir isomerism part kab ayega???

[@AllBoutChemistry]

Outer inner sphere k baad isomerism

[@archanasdevu]

Sir how the weaker bond have higher energy?? Plz explain

[@AllBoutChemistry]

the species which is less stable has higher eneregy than the species which are more stable, this is common trend in Chemistry which is followed by all intermediates, complexes and bonds, so a weak bond will be less stable and thus it will have higher energy.

[@archanasdevu]

@@AllBoutChemistry sir if the bond length is larger then bond energy and bond strength decreases. Can u xplain

[@mackumar2890]

@@AllBoutChemistry I think if bond is shorter n stronger then it requires more energy to break that bond

[@bonoshree8159]

In d6 why eg orbital is filled with 3 electrons?

[@ayushimishra7526]

Sir last me thoda samjh nahi aya.....😫😫 Jisme eg empty hota hai wo inert hote Hain!?!???

[@knowingchemistry735]

Yes. Eg main agar electrons aa gye toh us complex ne labile hi hona hai .

[@dimbeswarbhumij8026]

@@knowingchemistry735 kyun???

[@knowingchemistry735]

@@dimbeswarbhumij8026 the eg set arises from interaction with the ligand donor orbitals; this set corresponds to a σ antibonding level.since when electrons goes in antibonding the bonding of ligand with metal is weak therefore the complex will be labile and easily undergoes substitution. I hope it cleared ur doubt.🤗

[@dimbeswarbhumij8026]

@@knowingchemistry735 thnk u so much

[@dimbeswarbhumij8026]

@@knowingchemistry735 may i ask one more qstn??which book should i follow in order to build some good concepts regarding this topic???

[@vismiforever8357]

d6 high spin wrong it should be t2g 4 and eg 2

[@RakeshKumar-oq1xq]

8:24 vbt

[@parthshah3943]

D8 is most inert

[@vershabhardwaj2454]

Mistake h . d1. d2. d3 inert honge.. and d6 high spin me mistake h

[@movielink3495]

That that that. What the fuck!!!

[@bishnupriya7256]

Not understood.

[@gumnaam9731]

... D8 inert hota h yrrr🤦‍♀️

[@faiyazahmadalig897]

D⁸ is inert not labile

[@pratyushkrishna6071]

It's nice but try to speak in a fluent english otherwise opt hindi.

[@pritamborah5581]

First you should understand this topic yourself. After that you should try to teach other.

[@maclakhan522]

ajeeb angrezi h it would be better agr ap native language men smjhate…i am unable to stay focused

[@OpeDJ]

Thank you Sir

[@kollibalakrishna314]

Thank u sir

[@TheSanathanWorld]

Bro u can create a what's app group.

[@seetaramyadav4456]

Thank you sir

[@thendralarasic3269]

Thank you sir

[@susmiraja]

Thank u sir