China | Can you solve this ? | A Nice Math Olympiad Radical Simplification

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Learncommunolizer

Learncommunolizer

Күн бұрын

This is an interesting question with amazing concepts!
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Пікірлер: 12
@gustavosalcedo3092
@gustavosalcedo3092 3 ай бұрын
Greetings professor. Thank you for sharing your knowledge. You are truly a very intelligent man!
@SaucyCinemaFilm
@SaucyCinemaFilm 3 ай бұрын
Whew! Tour de force!! Buried within here is that (1 + √5)/2 is the number PHI, aka, “The Golden Ratio” which does reduce to x^2 - x = 1. And furthermore phi^n - phi^(n-1) = phi^(n-2)
@thomashorine9198
@thomashorine9198 3 ай бұрын
You can use polynomial division to write x^12 as q(x)(x^2-x-1) +r(x), where r(x) is at most linear. Then the value sought is r evaluated at phi.
@cyruschang1904
@cyruschang1904 3 ай бұрын
((1 + ✓5)/2)^2 = (3 + ✓5)/2 ((1 + ✓5)/2)^4 = ((3 + ✓5)/2)^2 = (7 + 3✓5)/2 ((1 + ✓5)/2)^6 = ((3 + ✓5)/2)((7 + 3✓5)/2) = (9 + 4✓5) ((1 + ✓5)/2)^12 = (9 + 4✓5)^2 = 161 + 72✓5
@keizerantares
@keizerantares 3 ай бұрын
The final answer is 144×PHI + 89 Reason is that you en with (PHI^4)^3 which gives you (3PHI + 2)^3 This yields: 27PHI^3 + 54PHI^2 + 36PHI + 8 Which gives in turn: 27(2PHI + 1) + 90PHI + 62 This gives: 54PHI + 27 + 90PHI + 62 And we get 144PHI + 89
@MuhammadSharjeelAnsari-s8w
@MuhammadSharjeelAnsari-s8w 3 ай бұрын
Professor use complex method.
@migueldia9771
@migueldia9771 Ай бұрын
cool
@NouraNor-h1x
@NouraNor-h1x 3 ай бұрын
تبارك الله عليك
@mathforallbyn.r6653
@mathforallbyn.r6653 3 ай бұрын
❤❤❤ #naweenraaj
@kambizkhosravi6138
@kambizkhosravi6138 2 ай бұрын
set it equal to x and take the Log.
@NouraNor-h1x
@NouraNor-h1x 3 ай бұрын
متابعة من المغرب
@MathSync
@MathSync 3 ай бұрын
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