Log Equation but with Different Bases

Solving log equations with different bases can be tricky.
In this video, one can learn how to change the base of one log so that it matches the base of the other log expression.

[@kdog3908]

Did not know this property of logs. Makes perfect sense, given some thought. Thank you!

[@calculus988]

Wow. I'm always learning new logarithm properties. I wonder how many logarithm properties exist in math. Is it infinite? 🤔

[@superacademy247]

They are NOT infinite but we've quite a bunch of them. According to my experience logaithm properties are better studied by practising.

[@TheMathManProfundities]

This is just a result of other laws i.e. logₐx=ln x/ln a=bln x/(bln a)=ln xᵇ/ln aᵇ=log_{aᵇ} (xᵇ).

[@ambienteSKATEvida]

Hail from Brazil! Nice solution

[@AprendiedoconAlex]

I will teach this rule next year to my students. Thanks.

[@mrhtutoring]

All the best~

[@逸園-無毒果園]

base=2, we have (1/4)log2(x)+(1/2)log2(x)+log2(x)=7,so log2(x)=4, x=2^4=16

[@studyholic._.13]

This is such a save when you have a math test on log tomorrow 😭❤️🌟 Thank you so much!

[@ekbalmokhammad8620]

Thank you for your teaching 🌹 I like your teaching 🌹 You are very kind teacher ❤

[@danielsoy1233]

It was awesome.

[@danielsoy1233]

can you teach me on about integretion and limitations.

[@atlascoo9647]

Thanks teacher

[@billclintone9701]

That was impressive.

[@harrymatabal8448]

Excellent method

[@user-km2fh5zi7p]

log16(x) + log4(x) + log2(x) = 7 log2⁴(x) + log2²(x) + log2(x) = 7 1/4 (log2(x)) + 1/2 (log2(x)) + log2(x) = 7 log2(x)¼ + log2(x)½ + log2(x) = 7 log2(x¼.x½.x) = 7 (x¼)⁷ = 2⁷ x¼ = 2 x = 2⁴ x = 16

[@louf7178]

Nice

[@ayunda.alicia]

How come

[@omargameover5438]

log2(x+x2+x4)

[@user-km2fh5zi7p]

@@omargameover5438 ?

[@user-km2fh5zi7p]

@@ayunda.alicia By Using properties of logarithm

[@louf7178]

Nice

[@tiago.alegria.315]

Very good thanks for sharing

[@zenersmytok3619]

This is brilliant.

[@chouchfroukh]

Great

[@eccentricaste3232]

That's a good one. Thank you.

[@prachi6597]

thank you sir 🙏

[@TheMathManProfundities]

You can't just say that because the powers are the same, x = 16. For example, x²=2² has two solutions, x = ±2. In this case there are actually seven solutions, the other 6 being complex numbers. So x = 16e^(2kπi/7) ∀k∈ℤ∩[0,6].

[@anestismoutafidis4575]

log16(x)+log4(x)+log2(x)=7 log2(4x)+log2(2x)+log2(1x)=7 log2(4•2,52)+log2(2•2,52)+log2(1•2,52) log2(10,08)+log2(5,04)+log2(2,52)= 3,33'+2,33'+1,33'=7 x=2,52

[@蔡木章]

Very good

[@mrhtutoring]

Thanks

[@shalomberhanu-ql7hs]

Genius guy

[@ashfakalin8637]

Sir, please upload some videos on integration.

[@LubegaHenry-vn8dv]

Am from Uganda en i love the way you calculate math problems. Am requesting u to use us differential equations thank u very much ❤❤❤❤❤❤❤❤❤❤0:00

[@qzvl]

interesting, I didnt know this was a property of logs. very useful though, thank you.

[@mrhtutoring]

You're welcome!

[@sajidrafique375]

Our math teacher never taught us such details of logs

[@user-km2fh5zi7p]

@@sajidrafique375 Yeah you are right although where are you from ?

[@sajidrafique375]

@@user-km2fh5zi7p Santa Barbara city college , caifornia but i was a foreign student there from pakistan ..

[@FlexGC]

Could he have used the base transfer formula instead?

[@catherinemarsh5453]

How many people accidentally square or power to 4 the 7 on the other side.

[@edwardarthur3439]

Maybe at the end just 7logx = 7

[@deewanapotta7]

he x should be 2 also if u just write power before log and put it on x head it be 2 powe 7 is x pow3er 7 so x is 7

[@getnetasnake7290]

🤗

[@ahmadsobh9566]

Very helpful. If only you don't use writing in colours other than white and yellow. Both colours are perfect and visible

[@mrhtutoring]

Ok next time

[@peterpzazz2441]

Sure….it’s easy for a math genius…..