NMR spectroscopy in easy way - Part 1

[@bhavishapatel8510]

Hello.... I am not from the physics background so was struggling to understand this; you explained it so well that all my basics about NMR is now clear.... Thankyou so much!!!

[@egpat]

Glad it was helpful! Thanks for watching.

[@prathyushad6665]

The best video on NMR. Clear with appropriate examples and concise. Thankyou Sir

[@egpat]

Glad it was helpful! Thanks for watching.

[@barbaradiasbiomed]

This was the only video that helped me better understand the basics of NMR, after watching several videos. Thank you.

[@egpat]

Great to hear! Thanks for watching.

[@devrathod2372]

Your way of explanation is too good. Truly this video is helpful for easy to understand about NMR spectroscopy . I 💜 it. Thank you so much for valuable information.

[@jikkimroy7958]

It is for the first time I could understand The NMR spectroscopy Thank you sir and expecting more and more videos

[@egpat]

Glad it is useful. Thank you. Definitely I will upload more videos, let me know any specific topic you are more interested. Thanks for your interest.

[@sangamthakre8799]

Can u give me ppt of NMR spectroscopy

[@prashantkumarparmanu]

he is the best teacher . A true spirit of a mentor . The Real Man .

[@egpat]

Thanks for liking.

[@pratiksaha7699]

Great video sir! loved the explanation😍 I also love the way u say "Protawwn"

[@egpat]

Thanks!

[@FeelEveryShorts]

You are the best teacher.

[@addu_mansoori]

Thank u legend 🎉

[@jubairiyajubi3972]

Well explained . Concepts are clear sir . Thank you so much

[@lauren9095]

Thank you for this helpful video! I really appreciate it :) On a side note - I noticed that at 11:09, the m value for I = 0 should be 1, not 0 (as presented).

[@pratikshetye7004]

No I guess I = 0 and m should be = 1 and not 0 as presented

[@pradeepbhakar6029]

Yes m should be 1

[@manikantapavan6427]

Hi, Nice explanation.. It would be better to describe why Resonance term is used in the technique.. and please check once regarding "No spin " in "No external magnetic field". The concept is, in no external magnetic field nuclei with 1/2 spin will be arranged in random, when an external magnetic field is applied, the nuclei with 1/2 spin will allign to the field. And further is as described. Ignore it, if it is irrelevant.

[@egpat]

Ya, that's a good point. You are correct, as you said, in absence of magnetic field nuclei will have random spin and they produce a small magnetic filed. These nuclei will have intrinsic angular moment but the net spin of all nuclei is very nearer to zero due to random orientation of individual spins. So practically it can be considered as net zero spin compared with nuclei with spin oriented with or opposite to external magnetic filed when it is applied. Thanks a lot for your interest and suggestion.

[@sireesha_2024]

Explained in simple way..tq sir

[@pradeepbhakar6029]

12:19 i think the multiplicity in case one is m=1 as 2i+1 and i =0 then m is equal to 1

[@vps1705]

Clear understanding to any chemistry students

[@SurajSingh-xv6rv]

Thank u you sir it is really helpful and easy to understand 👍

[@aswathim6684]

Very good explanation

[@maddumounika2977]

Thank you sir. This video helped me a lot👌

[@egpat]

Glad to hear that. Thanks for watching.

[@vishavjitsingh3451]

Well explained

[@vps1705]

Excellent teaching

[@prasunaponnuru9046]

Very good sir,ur lecture is very clear& easily understand to studends,thank u verymuch🙏

[@hrucha98]

Excellent explained wow👍

[@runningpharmabypriya7834]

Thank you very much for such informative session

[@egpat]

It's my pleasure. Thanks for watching

[@KalaiSelvi-ss1lz]

Very nice explanation sir.upload more videos sir

[@karthigajagadeesan5177]

Super sir.good explanation

[@pavisreviews3041]

Crystal clear 👌

[@helionyanna4655]

Well explained 👌🏻 ..... Thank u sir 🙂

[@egpat]

Glad you liked it. Thanks for watching.

[@pujachaurasiya7751]

Thank u sir, explained well..first time I understood the topic spectroscopy .

[@egpat]

Glad to hear that. Keep watching.

[@dwtrowe]

Beast

[@Deevena970]

You are a good teacher. Thank you

[@egpat]

Thank you! Keep watching.

[@mahmadgondal4933]

Sir ... I have a question When we provide RF the electrons can also absorb the radiation,so why nuclei absorb???

[@naseehan8856]

Very good ...in11:28 I=0,m=1 is right

[@egpat]

Thank you. Yes, as stated earlier in the video when I =0 , m value is 1. Thanks for watching.

[@naseehan8856]

@@egpat Yes right 👍 I watched 3 parts of nmr.very useful

[@brijeshprajapati6613]

Waoooo sir tq so much 👍🙏🙏🙏🙏🙏💐💐 unbelievable sir

[@sainiranjanreddymaguluri1694]

Thank u very much sir

[@shwethakachu8696]

Thank you so much sir

[@thamizselvi4823]

Nitrogen 14 is even, it is given under both odd.

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@dr.harleenkaur6932]

vvv nice explaination

[@cyrillvarghese3182]

Excellent

[@harshithathejaswini9518]

Awesome sir tqsm 🙏

[@egpat]

Welcome, thanks for watching.

[@Jatin_kumar_]

Sir how is value for I calculated?

[@sravanthi4312]

Explained excellently

[@egpat]

Glad you liked it. Thanks for watching

[@javeriasaeed2074]

The ever best video on NMR ,.... really helpful...thank you soo much 😊

[@mekdesbelete8766]

an outsanding explanation tnks sir

[@egpat]

Most welcome

[@biplabchatterjee2185]

Sir is 17O^2 is shown by NMR ACTIVE OR RAMAN ACTIVE..... please clarify my query sir

[@mahalakshmihr8918]

Tq soo much sir🥰🥰🥰👍👍

[@nusrat9127]

This way of teaching is very excellent

[@egpat]

Thanks for liking.

[@lalvarlawmhmar3722]

There can be signal for others than half

[@hemadictation123]

Nice explanation sir tq

[@egpat]

You're most welcome

[@veereshuppara6313]

Nice teaching 👌👍

[@egpat]

Thanks for liking

[@parthsharma6079]

You are from South India?

[@karanpreetsingh4654]

Nmr spectroscopy range please tell

[@olupotmoses275]

i feel am prepared for m MSC Exam now

[@akibansari47]

Nice

[@user-lt2cu1fo1w]

Which app you are used for making this video 😢

[@sandrasuja525]

Thank you so much sir...tht helped me to understand the concept

[@egpat]

Glad to hear that. Thanks for watching.

[@chemistryabcxyz2763]

The part 4 is not available. nmr spectroscopy in easy way part 4 egpat. How can I get it please

[@elmiranadirova2737]

12:36 tell it to deuterium NMR

[@khushbubedi1426]

Wao Thanku so much

[@egpat]

Welcome, thanks for watching

[@saiteja6742]

Never before ever after...

[@sainiranjanreddymaguluri1694]

In case 1 m=1 while comparing the cases there is m=0

[@annapooranir3054]

Really good and easy to understand..Thank you sir

[@abdurrazaq3657]

Sir ur explaining very well but try urdu or hindi .as for english so many british are there

[@sharmapharmacy4124]

Hlo sir very nice

[@mythilimohan3587]

Tnx to made tis🔥

[@egpat]

You are welcome. thanks for watching

[@MeIsUser]

8:56 doubt

[@bhaskarreddychinta2709]

Is nmr applicable to compounds that donot contain hydrogen?

[@egpat]

Yes, it can be used for silica and other inorganic compounds also.

[@midcrizzz812]

More than 1H NMR scientist will use 13C NMR...

[@dr.d.srividya4911]

We are supplying RF not EMR

[@pnsnarayana4714]

What is I sir

[@eagleacademy2346]

14 odd ????

[@harisonviju8331]

I wish my our online classes were like this..😁

[@chemicalworld7800]

Nmr active nuclei I should not be equal to 0....other than 0 can be anything not only 1/2

[@egpat]

When I value is 1 or greater it results in non-spherical charge distribution resulting in signals with variable line width which are not easy to study. But when I=1/2 it leads to spherical charge distribution which is easy to study. That's why nuclei with I =1/2 are selected for NMR spectroscopy.

[@chemicalworld7800]

@@egpat but we talking about nmr signal

[@egpat]

Yes, NMR signal better observed with nuclei I as 1/2. Can you give any example of nuclei studied in NMR with different I value?

[@chemicalworld7800]

Boran 11 Chorine 35 Both I=3/2

[@egpat]

That's great. You are right. So these are the quadrupolar nuclei. But here in this video we are discussing NMR spectroscopy for pharmaceutical analysis where we study nuclei mainly like proton, and carbon in organic compounds which have I value as 1/2. As you said, quadrupolar nuclei are useful to study inorganic nuclei like Cl and B. Thanks for your interest and watching the video.

[@kholazahoor9717]

N is 14 and 7 how can this be included in both odd? 14 is an even number!

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@aleemleem8110]

How can 14 will odd sir,,

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@nandlalsavaliya1849]

🙏🙏🙏🙏🙏🙏🙏

[@ramyasrircs9417]

spin quantum number is l not 'i' ...you have been constantly calling it "i"

[@soumyadeepsarkar7819]

Nuclear spin quantum no. is denoted by "I"

[@pradeepbhakar6029]

Bhai orbital angular momentum is "L"

[@donaldthustra_2997]

Nearly all of the information presented in this video is wrong. The claim that you can only observe NMR signals from spin-1/2 nuclei is especially agregious.

[@arnazmaryam539]

how desperate did i have to be to reach here:)

[@arunadhikari2303]

can I = 3/2 GIVES NMR

[@erikzuiderweg6824]

yes, and also I=1, but rhe signal is difficult to observe

[@kameshrajd9480]

7.26🤣🤣14 is odd number???😬

[@shindekrushna8170]

It is about number of neutrons bro, i.e. 7 and this is odd.

[@SouvikNagYT]

You dumb, sir is talking about neutron number which is odd

[@dranjups8911]

It's based on number of protons and neutrons, it's odd in number...

[@ranaalimudassar5859]

😂😂

[@pradeepbhakar6029]

Individually the number of protons are 7 and neutron is also 7 therefore these both are odd

[@j.hephzibahpriyadarshiniix5199]

Thank you very much sir

[@egpat]

You are welcome.