Projectile Launched of a Cliff

[@AmitojSingh_2402]

Real ones know how it feels when you solve the question first and then watch the video and get the correct answers. Little motivation boosts fr fr

[@estebansanchezsevilla1930]

whoever unliked this video has 24 chromosomes cus this was the most clear and simple explanation of a horizontal projectile throw

[@dirrdevil]

I just downvoted your comment. I have negative chromosomes.

[@XXmmXXgamer]

I am a student in KFUPM and really your videos are very helpful in our physics courses>> thank you

[@habtiemelke7966]

You are really amazing. The way how you explain it and how clearly you did it 🙏. Thank you and keep up the good works 👍

[@PhysicsNinja]

So nice of you

[@Xavier-nn4gs]

thank you for saving my life i really needed this.. TYSM I CANT THANK YOU ENOUGH

[@ericpalmateer806]

Finally! Now I understand why the acceleration is zero in the x direction! And even, I should have put it together on my own, now I understand why that means the x direction velocity stays the same too!

[@georgemathew8218]

You may also watch my video

[@viaangsumod-ong3557]

Best explanation! This helped me a lot! Thank you so much sir🙏🏻❤️

[@nizanare2188]

This tutorial is so simple and clear🤩 Thank you sir💖

[@can_with_beans]

I handed my physics notes from last year to a friend that's a year younger, forgetting that I'm probably going to need it lol. At least I know that I have some of the best resources (aka this youtube channel)

[@newtonokojie5555]

Thanks 👍. I understood it because u took your time

[@Yoaster06]

very easy to follow and understand thank you

[@صلاحالحراصي-غ1ض]

Perfect explanation 😍 thank you

[@romy8929]

Good explanation Useful video Do more on projectile

[@PhysicsNinja]

Thanks! Check out my other videos on projectile motion.

[@romy8929]

Physics Ninja can u show how to simplify quadratic equation and get time t values?

[@dipinnaik5578]

Thank you sir this was really helpful

[@chawrlie7040]

Bruh you made it a lot harder than I had to be

[@0niism]

oh my gosh thank you so much u saved me

[@coleguy27]

Great video

[@Fati_Alien]

damn i need to find the initial velocity :(

[@nchimunya6569]

When finding time the ball remains in the air the formula should be y=ut-1/2g(t*t).... therefore the answer will be 3.09s

[@soteri787]

I was following along fine until you got to trigonemtery. I understand that too, but why isnt the equation done with the hypotenuse?

[@c.m.p2943]

Thanks a lot sir

[@PhysicsNinja]

You got this!

[@ahmedhanafy4860]

you make a mistake because the question has a velocity of 20m/s and the law t equal to root 2H/g work with no initial velocity

[@AmirKhan-hy8ur]

thank u sir

[@brucejohnson5786]

why does vy turn positive?? wouldnt -9.8(1.75) be negative? a bit confusing

[@PhysicsNinja]

ooops, i forgot the -ve sign... sorry about that. Velocity is down, which i defined as the negative direction.

[@marwaitani1520]

Ur a lifesaver

[@shahbazahmad7833]

I dont get why g=-9.81 ? if its moving downwards cuz of gravitational acceleration , shouldnt it be +9.81 ?

[@felipoboyfelipie7541]

How did he get the 2 in the bottom

[@andyheinrich4755]

Tqvm u save my brain today

[@maralphayer501]

why was time not doubled? thanks

[@ashwinchander1837]

what about a single stage rocket?

[@dulcezubia3152]

For the Vy you multiplied negative times positive. Is Vy not negative?

[@cosimocubing3820]

yea i was also just super confused about that... his mistake.

[@zainabnoori9728]

1. A ball is projected horizontally from the edge of the table that is 1.00 m high, and it strikes the floor at point 1.20 m from the base of the table. a. What is the initial speed of the ball? b. How high is the ball above the floor when its velocity vector makes a 45.0˚angle with the horizontal? please help in b

[@vincentagustin510]

When the velocity vector makes a 45 degree with the horizontal, it means that the horizontal component and the vertical component of the velocity at that point is equal (tangent of 45 degrees is 1/1 =1). The velocity from part a is 2.67 m/s. This is always the horizontal component. At 45 degrees, this is also the vertical component. Use the kinematic equation using this value of the y-velocity, you get a height of 0.3637 meters from the top of the table. Since the table is 1 meter high, 1 minus 0.3637 equals 0.636 meters above the floor.

[@vincentagustin510]

Is this the answer you got?

[@zidamv1944]

shouldnt the g be negetive?

[@lourenco913]

is it possible to use work-energy therem here to find v?

[@PhysicsNinja]

Yes of course

[@lourenco913]

@@PhysicsNinja thank you !!!!

[@agus-__-tin7966]

Ok well ik what grade I’m getting tmr 😂😅

[@chl6161]

how would I find the angle at which the projectile (in the question I'm stuck with its a cannon ball hitting a ship) collides with the ground/object and the resultant velocity of the cannon ball hitting the ship?

[@PhysicsNinja]

You need to find vx and vy just when the projectile will hit the ground. vx=vox and vy=voy-gt. use the time when it hits the ground. Once you know both components of velocity you can use trigonometry to find the angle. tan(theta)=vy/vx and solve for the angle theta=atan(vy/vx). Hope this helps!

[@blepblop8213]

Thank youuuuuu

[@ianne178]

How to find the height?

[@reddeyezovnite9806]

GOOD PHYSICS NINJA EXAMPLE==ZERO BABBLING INSTRUCTOR VIDEO++INSTEAD EASY 2 VIEW GEOMETRY 2 HELP SOLVE PUZZLES.

[@armanigenes]

Easy