Physics 13.3.2a - Joule`s Law

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@alamIbbar 12 жыл бұрын

Thank you, sir, for creating these excellent videos. I was having some trouble understanding the concepts of electricity, and I turned to your videos to provide me with a fundamental understanding of how these concepts work.

@dsjtravels 7 жыл бұрын

i passed my exam because of this thanks!

@massoomaalrshim2244 3 ай бұрын

Thank you so much, you've made so clear to me. I truly appreciate it

@B1itZKr3iGC4 13 жыл бұрын

@derekowens i found this to be very good even though its more like a refresher to me it doesnt hurt to reread or rethink or even remind yourself what you know what you dont

@yesman1231 12 жыл бұрын

you can generate the formula for ohms law by breaking down one volt (Volt=Joule/coulomb) into SI base units. also ive been looking eveywhere for a video that equates formulas by using the SI base units but there dont seem to be any. i might look into making them myself.

@sadiyabudroo3249 7 жыл бұрын

Thank you so much. This law was not easy to learn on my book but its seems quite easy here.

@朱玉婷CHUYUTINGQ3608 3 жыл бұрын

Finally, I got it. Thanks.

@solanine6452 4 жыл бұрын

Why is it then that the formula can be rewritten into P=U^2*t/R?

@linhvu-bj4dh 9 ай бұрын

Maybe you are confused, we have Q=U^2*t/R because of U=I*R -> U^2/R=(I*R)^2/R=I^2*R

@javierjjs 5 жыл бұрын

You said that the conversion of electrical energy to heat is 100% efficient. What about the light that is produced by glowing resistors like a heating coil such as on an electric stove?

@derekowens 5 жыл бұрын

Oh, that's a good point! Okay, that light will eventually strike some surface and be absorbed, and when that happens the energy from the photons cause the atoms of whatever absorbed it to shake just a little bit more, and that is heat. The exception, though, would be the case where some of that light radiates away into space. In that case, it would just travel across empty space and might not hit anything for billions of years, so it would be radiant energy and not heat energy. So you are correct, the conversion to heat in that case would not quite be 100% efficient.

@B1itZKr3iGC4 13 жыл бұрын

@derekowens nice channel i recently went to classes in highschool about four years back that was supoosed to allow the students to gain a certification to work on electronics legally in the US unfortunately the state stopped paying for the class because some ppl dropped out they said theyd pay for the certification tests only if 25ppl attended never flunked or left the class

@MrPlankton996 6 жыл бұрын

What about the devices that are not used for heating? How do we calculate how much heat they dissipate, and how much heat is used for useful work? In case of heaters, dissipated heat is basically useful work :D.

@tarapreethmutyala4455 11 жыл бұрын

Really a good video. I don't know much , but i think resistance and temperature are related .The temperature changes right ,as you said.Heat is released continuously .So will there be any change in resistance

@lutandar5937 8 жыл бұрын

These videos are soo helpful! - Thanks!

@struggler98 12 жыл бұрын

how can you apply ohms law and the electric resistance Temperature is changing

@nickayivor8432 8 ай бұрын

Outstanding tutorial 👌 👏 👍

@tuttar3 10 жыл бұрын

So if you have: 10^2 A * 1k ohm * 1 sec = 100.000 J When you convert that with online celcius converter i give you: 52.66 degree celcius That means the resistor should go from 1 to 52.66 C* after 1 second. Does that sound approximately right to you guys?

@derekowens 10 жыл бұрын

I'm not sure what assumptions your converter was using, but it would depend on the mass of the resistor and the material it was made from. But yes, it should heat up quickly in this case. 100 Amps is a lot of current.

@RameshSharma-cw7bw 9 жыл бұрын

+tuttar3 The figure which you converted into degree celcius is actually the heat generated by the resistor. In other words, by this amount the resistor heats up. But to determine the temperature raise, we need the heat capacity of the material of resistor (how much heat will raise the temperature by 1 K or 1 degree celcius).

@TheBigBangggggg 7 жыл бұрын

He did use 10 Amps, Derek, and put that in the equation for H.

@kyleva9903 6 жыл бұрын

Simply the resister is a load

@cedricproper5256 6 жыл бұрын

You had me at P = I^2R.

@tasnimtishma6632 3 жыл бұрын

Thanks sir....!! 🤠🤠

@sunnyhound0 11 жыл бұрын

Thank you for explaining this!

@gouhuskies 14 жыл бұрын

So, I'm confused. Is Joule's Law H = I^Rt or is it P= I^R? (Sorry I have to use the ^ symbol for squared) or is it both depending on whether or not you're looking for power vs. heat?

@barbarannop1799 5 жыл бұрын

im wondering the same ting, but I think what it means is that P = I^2 R is Joules Law for Power and the other one is Joules law for heat. Someone correct me if im wrong

@halodude178 12 жыл бұрын

hey im 13 and kinda new at physics. Im highly interested in Quantum Machanics and study alot about it. My father recommened learning this. Im just not understanding quite well. Could you please help me and explain it to me. Thank you!

@theuniverse3782 3 жыл бұрын

hey how are you doing now its been 8 years

@ankithutch 14 жыл бұрын

WoW so basically structured the video thanks.....

@KSITREVS 12 жыл бұрын

I am just going in to college and I am curious, Is this university stuff or A-Level. I am a huge fan of electronics and this channel is pretty damn awesome Thank you for your videos! See you around

@charityentertainment 2 жыл бұрын

WHAT ARE YOU DOING NOW

@KSITREVS 2 жыл бұрын

@@charityentertainment big boy stuff