Physics 29 Efficiency Of Heat Engines (13 of 14) The Carnot Cycle

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Michel van Biezen

Michel van Biezen

Күн бұрын

Visit ilectureonline.com for more math and science lectures!
In this video I will explain and develop the efficiency equations of the Carnot cycle.

Пікірлер: 49
@physicsexplainedsimply114
@physicsexplainedsimply114 8 ай бұрын
Michel you are honestly the greatest teacher I have ever had and I dont even know you, thank you so much for these videos I genuinely would be in a massive pickle otherwise. I wish you all the best
@MichelvanBiezen
@MichelvanBiezen 8 ай бұрын
Thank you. Glad you find our videos helpful.
@anusharma6090
@anusharma6090 7 жыл бұрын
Why aren't you my physics teacher??!! You are too good at explanation
@bios546
@bios546 10 жыл бұрын
WOOOOOOOOOOOOAAAAAAAAAAAAAAAAAAAAAAAWWWWWWWWWWWWW... my greatest doubts... are clarified!! thanks to u sir!!!
@XplosiveAction
@XplosiveAction 3 жыл бұрын
If we are looking at the absolute value in the end, of the quantity QC/QH, are you essentially saying that we can calculate QC and QH using the initial equations, and just saying "we know that the magnitude of each values are representing simply how much heat is added or removed" its kind of like, the negative sign is saying that too
@salliet9653
@salliet9653 6 жыл бұрын
thank you sir. your lectures have really helped me. I didn't get why you took the absolute value for Qc/Qd.
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
Because we only wanted the ratio, in order to find the efficiency. (Positive Q = heat ADDED to the gas, negative Q = heat REMOVED from the gas)
@biancapena1355
@biancapena1355 4 жыл бұрын
Dr. Biezen, you have saved me in my Engineering Physics I and II classes, and now for Thermo. Thank you for your work! You broke down the concepts of the Second Law perfectly! I haven't struggled on my homework. :)
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
Thank you for your comment. It is good to know that our videos are helping students around the world. :)
@rameshdas7788
@rameshdas7788 6 жыл бұрын
Thank you very much...
@g7sky
@g7sky 9 жыл бұрын
thanx for making this video ! this is the one
@allenmolina1269
@allenmolina1269 5 жыл бұрын
Hi Sir... Why Qc is positive even if Va is larger than Vb. When we take the natural log of that Vb/VA we'll get a negative sign. Vice versa with Qh... Thank you for all the knowledge
@nthumara6288
@nthumara6288 Жыл бұрын
can not we replace t insted of q when finding efficincy in pravtical engine
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
We use T (temperature) for theoretical engines like the Carnot engine. For real engines we need to use the actual heat exchanged, Q
@samexcelll123
@samexcelll123 2 жыл бұрын
Thank you Sir
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Most welcome 🙂
@historyisthebest5831
@historyisthebest5831 4 жыл бұрын
Professor, can you please make a few videos on practicing how to read PV diagrams fast? I don't think I'm proficient enough in reading and analyzing PV diagrams.
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
My suggestion is to go through each of the videos on the first law of thermodynamics and all of the videos on the various thermodynamic processes as well as the videos on PV = nRT. After that you'll have a full understanding of the PV diagram. (That is why we made all of those videos)
@historyisthebest5831
@historyisthebest5831 4 жыл бұрын
Is Qh suppose to be entering during path AB and not CD?
@andreapaulsen3006
@andreapaulsen3006 7 жыл бұрын
I'm sorry to say that your argument for only looking at the quantity not the sign is somewhat unclear. Qc is negative as you write it - because of ln(Vb/Va). Instead you should write e=W/Qh=(Qh+Qc)/Qh=1+Qc/Qh and then argue written with numerical notation e=1-|Qc|/|Qh| because 01. But that's just my humble opinion.
@historyisthebest5831
@historyisthebest5831 4 жыл бұрын
Actually the efficiency is e = Qh - Qc / Qh
@venkateshreddy3519
@venkateshreddy3519 9 жыл бұрын
best one
@drayushjain_
@drayushjain_ 9 жыл бұрын
Excellent.
@shaherbano1334
@shaherbano1334 7 жыл бұрын
Sir, why Temperature is discussed in Carnot Engine or Carnot Cycle instead of Heat Q as in real engine???
@MichelvanBiezen
@MichelvanBiezen 7 жыл бұрын
The Carnot engine is NOT a real engine. It is just a theoretical engine, that shows the maximum theoretical efficiency. A real engine can never reach of exceed this efficiency, and it depends on the operating temperatures.
@shaherbano1334
@shaherbano1334 7 жыл бұрын
Thanks Sir.
@fozymilograno
@fozymilograno 10 жыл бұрын
very good!
@naqeefhatta7782
@naqeefhatta7782 8 жыл бұрын
Hi Sir, I really like your videos. Do you mind going through Brayton cycle?
@MichelvanBiezen
@MichelvanBiezen 8 жыл бұрын
That will have to wait. Working on too many other topics right now.
@somaabdallah7917
@somaabdallah7917 8 жыл бұрын
please I would a course of carnot of non-reflective?!
@starwarsedison
@starwarsedison 9 жыл бұрын
very clear
@tsoojbaterdene7793
@tsoojbaterdene7793 4 жыл бұрын
We invented refrigerator.And It was nature law-breaking invention.
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
Yes, it is like making water flow up hill. It requires work.
@mizpahobcial8655
@mizpahobcial8655 6 жыл бұрын
where did the nRT and In came from?
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
PV = nRT
@annasarahkramerfazendeiro8030
@annasarahkramerfazendeiro8030 5 жыл бұрын
Why are we allowed to take the absolute value of QH/QC in the end of the video?
@MichelvanBiezen
@MichelvanBiezen 5 жыл бұрын
Because the ratio of Tc/Th can never be negative
@md.mominulislam5068
@md.mominulislam5068 8 жыл бұрын
Sir, how you cancel out the natural logarithms ? It is not clear yet.
@MichelvanBiezen
@MichelvanBiezen 8 жыл бұрын
+Md. Mominul Islam Because Vb/Va = Vc/Vd
@MohammadkazimHalimy
@MohammadkazimHalimy 10 ай бұрын
Video quality is so bad😢
@MichelvanBiezen
@MichelvanBiezen 10 ай бұрын
Yes indeed. We had a lot to learn when we started filming these videos.
@AlaaMohamed-ct5jt
@AlaaMohamed-ct5jt 9 жыл бұрын
why did you take the absolute value ?!!
@MichelvanBiezen
@MichelvanBiezen 9 жыл бұрын
+alaa ashraf Q is positive when added TO the gas and Q is negative when removed FROM the gas. Thus the ratio of Qc to Qh can be positive or negative and the temperature can only be positive.
@AlaaMohamed-ct5jt
@AlaaMohamed-ct5jt 9 жыл бұрын
Michel van Biezen the work total in Carnot cycle does it equal qin plus or minus q out ?? What the right rule is not plus or minus Because there are argue about that between people Can I have your email , because I have abother question concerning thermodynamics
@MichelvanBiezen
@MichelvanBiezen 9 жыл бұрын
+alaa ashraf The work done in any cycle equals the net inflow of heat (Q), since the change in internal energy is zero for any cycle. The sign for q only depends on how you define the first law of thermodynamics. (Look at the video on the first law of thermodynamics. )
@AlaaMohamed-ct5jt
@AlaaMohamed-ct5jt 9 жыл бұрын
Michel van Biezen can I have your email ?
@satyamkumar567
@satyamkumar567 6 жыл бұрын
Video quality is very poor
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
Apologies...When we first started our KZbin educational channel, we had ABSOLUTELY NONE, ZERO experience in video-making. We were math/physics not film-making majors. So we had absolutely zero clue about lighting and sound. Fortunately we do have a learning curve. So our “less old” videos have better lighting, focus, and sound.
@ajavier38
@ajavier38 6 жыл бұрын
@@MichelvanBiezen It's still a great and helpful video!
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