Q. 3.3: Simplify following Boolean expressions, using three-variable maps: (a) xy + x'y'z' + x'yz'

[@sharathchandra6349]

Sir ,b is wrong.correct answer is x'+yz

[@DrDhimanKakati]

Yes, you are correct. Thanks for point the mistake

[@manjotkaur2700]

can you please explain the question?

[@ANOLDMUNISHI]

The answer of professor is pure correct because the x is constant

[@ANOLDMUNISHI]

Now I have understand where is the mistake 🙏🙏

[@salmanmasood1421]

Sir thanks u ... Help me a lot ♥️ Mistake in (b) part x'yz' 1111 0010

[@hyon3654]

You are my hero

[@adityakr7586]

2nd is wrong simplified

[@alizafar5481]

thank u the thumbnail helped me a lot

[@theshadypersonify]

Did you make an annotation in the video for the correct answer for b? x"+yz

[@DrDhimanKakati]

I have added in the description section of the video

[@ANOLDMUNISHI]

The answer is correct

[@duamardeep]

well explained

[@abhijitpatra9216]

Thank you sir it's really helpful 🙏

[@t.sure_is_nokidding4453]

so good,help me a lot

[@arshadsiraj3162]

Sir b is wrong

[@aleezaHabib-e4g]

its good but you B part of question is little bit wrong . last X not Y and Z not are not write correct

[@duamardeep]

thankyou sir

[@Harsh-so2zk]

Thank u sir 2🙏

[@eishaafzaal1960]

That was really helpful

[@pachabhanuprasad574]

Simplify the Boolean Expression AB'C+A'BC+ABC , how can we simplify sir

[@KamalSubedi09]

Thanks

[@dhoni_dhoni-iu9el]

Thank you please kindly put all answers for the questions in 3rd chapter please

[@DrDhimanKakati]

By this week i shall upload upto 3.11

[@dhoni_dhoni-iu9el]

@@DrDhimanKakati put how to find prime implicants and essential prime implicants

[@DrDhimanKakati]

@@dhoni_dhoni-iu9el A prime implicant is a product term obtained by combining the maximum possible number of adjacent squares in the map. If a minterm in a square is covered by only one prime implicant, that prime implicant is said to be essential.

[@dhoni_dhoni-iu9el]

@@DrDhimanKakati thank you brother

[@donhjoe2162]

How can I simplify this expression? x2'+x3x4+x3'x4'

[@Aakib_Swakkhor]

Can you please check on minute 4.07 sec. ?

[@garbaochayan]

Yes he made a mistake , it’s not Y’

[@Codewithme-67]

XY'Z + X'Y'Z + XYZ Simplify it. Thank you

[@nv4492]

thanks a lot.

[@DrDhimanKakati]

Most welcome!

[@abdulbasit477]

Bis wrong because sir does not put the 1 in the bock of m2 or x'yz'.ok

[@DrDhimanKakati]

I have added this in the description section

[@ANOLDMUNISHI]

Now I have understand the mistake

[@lucydragneel6637]

x’z’ + xyz+xyz’ simplify this plss

[@DrDhimanKakati]

x’z’ + xyz+xyz’=x'z'+xy(z+z')=x'z'+xy

[@anishkoirala2237]

I dont understand c number answer bro

[@Zbraj3]

2nd part is wrong

[@ranvijay2791]

ur b part is wrong i guess

[@mohankumar1351]

B galat h sir

[@md.abirhasan7089]

B IS X' +YZ

[@ANOLDMUNISHI]

Why

[@Shogun507]

@@ANOLDMUNISHI He forgot to write the third term i.e x'yz'.