RC circuits with pulse input (Part 1) || Prep for interview

charging and discharging of Capacitor

[@HimanshuAgarwal_]

kzbin.info/www/bejne/a4a9Z5KQesqmask For English Viewers and Better understanding of the topic. Visit my Website to see all my placement courses. You can simply follow my placement courses for the preparation of placements in Analog VLSI Domain. himanshu-agarwal.netlify.app/

[@elkrutarth]

thanks, himanshu for posting ! I am an embedded design engineer, I did masters in electronics 5 years ago... still enjoying RC circuits... I used to calculate the sums given in network analysis by van vekenburg and pulse digital waveform by millman....

[@HimanshuAgarwal_]

Thanks sir. Means a lot to me 😄

[@HimanshuAgarwal_]

There is one thing I forgot to mention in this video. In each case, for RC >>> T, the output will stablize (or steady state value of output) at Vi/2 (5/2=2.5V in this case) The reason is that in each case, Speed of Capacitor charging is getting reduced, and capacitor discharging is getting increased per cycle. That's why output will stablize at Vi/2 with some ripple. You can also understand it by the concept of Fourier series.

[@hariharakumar891]

So, you are saying at some point both charging and discharging rates become same and output will stabilize?

[@prabhjotsingh5916]

Could you plz explain it how?

[@kummarapoojith9544]

Could you give a hint on how we can use the Fourier Series for analysing the circuit?

[@biprobhadra1102]

@@prabhjotsingh5916 Actually if you look keenly in the ckt exactly what is happening like when Vin is 5V then capacitor will be charging but in each cycle because of initial voltage acquired by the capacitor that's why current is decreasing hence charging rate will decrease and when Vin is 0V that means Vin is grounded then only capacitor will behave as source to the Resistance so Capacitor will discharge through R but in each cycle because of initially charged up in the Vin =5V case and in Vin=0V case the current flowing through the ckt is increasing in each cylce so this will continue and in steady state something id increasing and something is decreasing so it will come up at middle position that is Vin/2 i.e. 5/2=2.5 V.

[@indshots8450]

I didn't understood plzzz care to explain ....

[@bangaloriansvlog]

Thanks for the detailed and simplified solution. ❤

[@MdZeeshanAlamOfficial]

Depression se bacha liya bhai apne. Sukriya.

[@HimanshuAgarwal_]

Correction - At 10:57 - Polarity of Vi is Opposite

[@CAPSTONEization]

this go me confused..thnx

[@hariharakumar891]

thanks a lot! This was the very video I was searching for. Neat explanation.

[@HimanshuAgarwal_]

Thanks for the appreciation :) You can checkout more RC ckts Questions in the playlist. Have dealt almost every possible configuration.

[@hariharakumar891]

@@HimanshuAgarwal_ Thanks for the uploads

[@sushmareddy5129]

Super explanation ❤️

[@CAPSTONEization]

man this was neat ..thnx

[@hakuna3132]

I was shortlisted for fit challenge texas instrument 2022,interview went good but still I didn't get through the technical round😕

[@tabluchakraborty7319]

Can you please discuss pulse current excitation,step current excitation of RC ,RL and RLC circuit intuitively

[@HimanshuAgarwal_]

Will do it in Feb for sure.

[@vijayalakshmik8099]

I have a doubt Which one is voltage waveform and which one is current waveform

[@saisrikargollamudi7892]

@8:26 In second question, in which time constant is much greater than time period of input, what will be the steady state voltage, 5V or 2.5V?

[@HimanshuAgarwal_]

2.5 V Once, go through the comment section, you will find it there

[@saisrikargollamudi7892]

@@HimanshuAgarwal_ thanks, I forgot to check other comments,sir, can you make a video on solving circuits using Fourier series concept

[@HimanshuAgarwal_]

@@saisrikargollamudi7892 Here, Go through this kzbin.info/www/bejne/rKCvlGiIrcyNnqs

[@indshots8450]

​@@HimanshuAgarwal_ how 2.5???

[@tabluchakraborty7319]

Actually I have learnt with voltage excitation .. but if current excitation is given ..how can we intuitively think can you please discuss?

[@HimanshuAgarwal_]

Yes, I will discuss. It's nearly the same. I will discuss it soon

[@rayraysayshi5255]

Is this in English? Can you add subtitles?

[@HimanshuAgarwal_]

Will upload the same analysis in English soon

[@ProfessorGovalla]

Is this in English?

[@anuragmishra3227]

Nope

[@nike9142]

Too many ads bro while watching (in 19 mins video I got 4-5 times ads)

[@HimanshuAgarwal_]

I didn't put any ad from my side bro.

[@nike9142]

@@HimanshuAgarwal_ ok I think some utube algorithm...

[@Golukumar-vj6kk]

use brave browser. no ads on any YT videos.