I wish these videos (+FM) could be out 1 year ago... so good
@poorman-trending2 жыл бұрын
I’m struggling understanding where the side bands come from. If you are modulating the carrier, and the only thing changing is the amplitude, why would there be other frequencies involved?
@talltomb Жыл бұрын
Side band refers to the "bands" of frequencies on the X axis to the left and/or right of the carrier. The X axis is frequency and Y axis is "energy" of each shown frequency.
@gnosistalks9568 Жыл бұрын
@poorman8317 did you got the answer , cauz I'm stuck with the same point.
@TomR45911 ай бұрын
Carrier + modulation into a mixer sum and difference gets ur sidebands
@Eiarlk9 ай бұрын
I think its their Harmonics, depending on modulating signsl
@nohrtillman87348 ай бұрын
Every video explanation I look at just states “here are the side bands of different frequencies” and leave it at that. If the intelligence is in different frequencies its frequency modulation. The 1000hz modulation is in the magnitude (amplitude) of the fixed frequency wave. Not the side bands. Why is it always presented this way?
@4BohrKid2 жыл бұрын
Wow, this video helped me understand my AM modulation lab so much. Thank you 🙏
@pauldenisowski2 жыл бұрын
Glad it was helpful - thanks for the feedback!
@Daluk04 жыл бұрын
Thanks for creating this video series. But at timestamp 4:40, you need NdB as the input to the formula. So as m = 2 * 10^( NdB / 20 )
@pauldenisowski4 жыл бұрын
Yes, absolutely -- you can re-arrange the formula that way to solve for m given a measured value of N. This is actually how this measurement is normally made using a spectrum analyzer. Thanks!
@suchirasenevitathne7017 Жыл бұрын
This is very helpful to understand the basics of AM. Thanks.
@pauldenisowski Жыл бұрын
Thank you!
@sofianebenhamza49852 жыл бұрын
Thanks for your presentation , it's very rich and simple to understand
@pauldenisowski2 жыл бұрын
Thanks! Appreciate the feedback!
@sagunraul30314 жыл бұрын
Thank you sir ❤️❤️❤️❤️ from 🇮🇳 india
@frawding94383 жыл бұрын
Thanks for this. Really helped with my signals coursework
@ego-qx1wv4 жыл бұрын
Hello, just to point out that the amplitude of each sideband is half of the amplitude of the sinusoid: F{ Am*cos(ŋ*t) } = Am/2 [ @(f+ŋ) + @(f-ŋ) ] with @ as the dirac delta dist. Great Video
@pauldenisowski4 жыл бұрын
Thanks!
@DrGarry41454 жыл бұрын
Amplitude of sideband is not strictly 1/2 of carrier. You can change the amplitude by changing m ratio
@ESEben103 жыл бұрын
very good man! I would like just o ask something: I don't know if it is a misunderstanding mine or some mistake on the presentation, but I saw a contradition between the 3:30 and 4:56. On 3:30 we have a low signal changing for m=0.1 but on 4:56 a highly changing amplitude of spectrum for the same value of m. How to understand this?
@pauldenisowski3 жыл бұрын
Good question. The graph at 3:30 shows the signal in the *time domain* (power vs. time) and the graph at 4:56 shows the signal in the *frequency domain* (power vs. frequency).
@ESEben103 жыл бұрын
@@pauldenisowski then a low amplitude proportion in time domain can correspond to a high amplitude proportion in frequency domain?
@md.sazzadhossain18344 жыл бұрын
sir,will u explain me the sidebands please? i've many doubts about sidebands.
@manfredcaranci62344 жыл бұрын
There are upper and lower sidebands, or side frequencies. The UPPER sideband is made up of the SUM of the carrier plus the modulating frequencies, while the LOWER sideband is the DIFFERENCE between the carrier and the modulating frequencies. Modulation, whether amplitude (AM), frequency (FM), or phase (PM) always involves the production of sidebands.
@matinsb14 ай бұрын
@@manfredcaranci6234 why though? in case if AM, we are not changing the frequency of carrier signal... we are just changing its amplitude by a factor of modulating signals amplitude (Ac + Am or Ac - Am)
@tedwang2996 Жыл бұрын
why you draw the rf signal in sine wave, I mean the most common case, it is not sin/cosine?
@stormbytes3 жыл бұрын
Consider adding Greek 101 as a prerequisite.
@pauldenisowski3 жыл бұрын
(laughs) γηράσκω δ᾽ αἰεὶ πολλὰ διδασκόμενος :)
@johnlevis36482 жыл бұрын
Greetings from Greece
@nohrtillman87348 ай бұрын
Does not compute. At 2:42 in the time domain, the blue line (carrier) amplitude increases and decreases with time. Amplitude of the carrier frequency is clearly changing/modulating. At 4:22 in the frequency domain, the blue line representing the carrier at that frequency is suddenly now a fixed value. Further on at 5:16, the carrier amplitude is described as constant. Both cannot be true. Many people struggle with this. Just saying.
@ab_ab_c3 жыл бұрын
Wow! Very well done! Thank you!
@jhonelalbarracin74364 жыл бұрын
Thank you Senpai.
@yTb28010823312 жыл бұрын
Professional video !
@pauldenisowski2 жыл бұрын
Thanks - I try :)
@saleemraza27784 жыл бұрын
Thanks very very much. Love u
@kimkim54163 жыл бұрын
Thank you!
@hhatiget68984 жыл бұрын
good thanks
@ernstuzhansky2 жыл бұрын
Thanks!
@thatzaw70823 жыл бұрын
thank
@marcusanderson90424 жыл бұрын
When did you get Brent Spiner to voiceover this? lol
@pauldenisowski4 жыл бұрын
I could never hold a candle to Commander Data :) Besides, if you listen closely, you'll hear me using contractions ...
@alimuqaibel76194 жыл бұрын
You might find this video relevant: Amplitude Modulation the Big Picture kzbin.info/www/bejne/pavJeIBqntCpa6s
@remnantministries93982 жыл бұрын
This explanation of AM makes too many assumptions to be useful, not to mention it moves too fast.
@pauldenisowski2 жыл бұрын
The video does assume a certain amount of background knowledge - if you have suggestions about what "pre-viewing" content might have been helpful, please let us know!