Super Simple Trick to Solve for the Limiting Reagent EVERY TIME! Chemistry MCAT

[@sarahchong9616]

you're the reason Im going to get a 528 on the mcat

[@sarahchong9616]

update I got a 498 and now I am retaking it lmao

[@alifaraj312]

@@sarahchong9616you got this

[@aslaans.5654]

@@sarahchong9616 LMFAO I FEEL U

[@sophias4280]

@@sarahchong9616How did the second round go?

[@zazzawi0099]

My smile never disappeared so quickly 😆 I really hope you did great second time 🥰

[@DFOlover1]

Are you serious? It's really been this easy???

[@TheFutureGuyGaming]

thanksssssssssss really helpful!!!!

[@BUNNIELOBES]

Ahhh!!! Thank you for this!!!!

[@amberwolff4111]

How would you know if both reactants =2? For example, 1N2 + 3H2 --> 2NH3, for both reactants mol/c = 2

[@sciencesimplified3890]

If the number of mols/C for both reactants = 2…. Then neither would be a limiting reagent, both reactants would run out at the same time

[@eliasmoussa4008]

Did you give us the mols or are we supposed to know them? Like the 3 mol for C3H8

[@e.m.ye.m.y1779]

Thank you so much !! Do you have an email for inquiries ?? Thank you again

[@prinox1686]

bruhh !!! ❤

[@shawalbhalli9076]

When we calculate theoretical yield using the moles of the limiting reactant, do we use the moles before dividing with the coefficient?

[@sciencesimplified3890]

As opposed to what? But yeah I believe so I’m a bit confused exactly what you’re asking

[@Tert-Butyl]

I'm sorry but could you not just assume the one with the biggest coefficient is the limiting reagent? I feel like this is taking it a step further than it needs to go.

[@sciencesimplified3890]

Trust me, do not soley use to coefficient to determine the limiting reagent… there will be many examples of this on exams where that will not be true

[@sukhdevchaudhary241]

We can't understand your voice in English we can in English but your voice is soo diff please manage for us🙏