Hii In this video we are discussing a RC question asked in Texas. Thanks to Saimanikanta for sharing the question.
Пікірлер: 46
@analogeasy-peasy75592 жыл бұрын
@ 8:30 I have said the black wavefoem to be the input which clearly is by mistake. As stated in the video, the input is varying from Vp and 0 as a pulse.
@anirbanghosh25772 жыл бұрын
you can also discuss what if the input goes to -Vp rather than 0V
@pratikbharbat94512 жыл бұрын
U people are doing some next level things n making engineers life easy . Thnx for sharing experiences
@analogeasy-peasy75592 жыл бұрын
So nice of you
@amitjana8172 Жыл бұрын
very nice video Dada :)
@Zerjditywnskg4552 ай бұрын
thanks for sharing...there is no ground?
@mai-vv3yo2 жыл бұрын
Appreciate your work and effort. Its really helpfull 👍🙏I request you to Please do solve some questions on rc circuit with diodes
@analogeasy-peasy75592 жыл бұрын
Please mail some if possible.
@mirzaamaan69372 жыл бұрын
Bro if this same circuit is solved by laplace then the whole scenario is different at infinity output will be vin/2
@jashanjain84052 жыл бұрын
Well explained bro!! Thanks for these kind of series✌🏻😍
@analogeasy-peasy75592 жыл бұрын
Glad you liked it
@shashankmourya43662 жыл бұрын
We try🙂
@Gyan.2507 ай бұрын
Why in the negative cycle of input the out is not starting from - V. They all are parallel voltage should be equal. Why are sharing it between two cap.
@shashankmourya43662 жыл бұрын
p.s...my voice got disconnected due to bad network😐
@jashanjain84052 жыл бұрын
Your presence is enough 😌
@mrinalkantidebnath3046 Жыл бұрын
Can we solve this using laplace transform.
@JasonXavier-rk6kl2 жыл бұрын
Nice one 👍
@analogeasy-peasy75592 жыл бұрын
Thank you! Cheers!
@jashanjain84052 жыл бұрын
Shashank 🤜🏼always rocking 😎
@shashankmourya43662 жыл бұрын
Learned from the best 😜
@roswaldfrancis4632 жыл бұрын
A thevenin equivalent: vin/2-2C-R,hpf
@arslanbhatti97712 жыл бұрын
Hi, Thanks for the review. I had a question about the Vout(t=INF).. Will it be equal to 0 because capacitor discharging into C1 (the first capacitor) or will it be a capacitive divider like in your previous video .. in this case since C's are equal Vout(t=INF) = Vin/2 ? Appreciate your help. You are a great teacher.
@analogeasy-peasy75592 жыл бұрын
It (Vout(t=INF)) should be zero right as i have mentioned in the video. Thanks for the kind words ☺️
@arslanbhatti97712 жыл бұрын
@@analogeasy-peasy7559 appreciate the reply. Can you explain again in words why it's 0 at V(t=INF)?
@tanmayvadhera4250 Жыл бұрын
@@arslanbhatti9771 at steady state the capacitor connected to source will block the current. This means that the drop across the resistor , 'R' will drop to 0 i.e. Vout will drop to 0
@biprobhadra110211 ай бұрын
@@arslanbhatti9771 at t=infinity means at steady state omega=0 for a step voltage Capacitor will behave as a Open Circuit C1=C itself and in C2 || R the Resistor will dominant here since capacitor is at open ckt so o/p terminal equal to 0. As C2 has discharged all its voltage across R terminal and C1 has hold its voltage.
@praveenkumarmaddeti66682 жыл бұрын
At the end the input signal was taken as symmetric square wave instead of pulse signal. Apart from this.. It was nice and brief explanation..
@saurabhtrivedi61812 жыл бұрын
Pulse is a symmetric square wave right. You can confirm this from the Cadence Virtuoso tool bro.
@praveenkumarmaddeti66682 жыл бұрын
My point is he analysed the circuit for pulse input but in the diagram he has written symmetrical square wave..
@saurabhtrivedi61812 жыл бұрын
@@praveenkumarmaddeti6668 yeah, but the pulse input one time period is a square wave right!.. That's is what being analysed over here. The same output will be repeated for all the cycles.
@praveenkumarmaddeti66682 жыл бұрын
He analysed it for input that changes between 0 and Vp. But in the output waveform he has shown the input waveform that changes between -Vp and Vp.
@saurabhtrivedi61812 жыл бұрын
@@praveenkumarmaddeti6668 please see the last part where the two capacitor comes in parallel. They will come parallel only if input voltage is zero right!
@nidhigupta8970 Жыл бұрын
in last part of video; it says when input is zero initially it will got -v/2 ; bt according to me it should go -V becasue both cap connected in parallel ; correct me if i am missing something?
@biprobhadra110211 ай бұрын
No it should be -V/2 as the capacitor will instantly divide the charge among themselves as the charge should be conserved after that then it will discharge through R.
@MIKL7701 Жыл бұрын
Thank you very much sir for the great video, at 4:49 you state that vo is v/2, I would appreciate an explanation why?
@prashanthr377611 ай бұрын
Apply voltage divider rule for parallel capacitor. When input is =1. Solve nodal equation You’ll arrive with vout= (c.c)vin/((c+c)c) = vin/2
@hakuna3132 Жыл бұрын
I was shortlisted for fit challenge texas instrument 2022,interview went good but still I didn't get through the technical round😕
@analogeasy-peasy7559 Жыл бұрын
Happens man! Don't worry if you are doing your job honestly then something good must be waiting for you :) BTW what is FIT? written test I guess
@BALA-jw7nd2 жыл бұрын
Bro im having a small doubt. At t=0 the moment when applying sudden change in voltage 0-V volts the capacitors will be short circuited and the voltage at the second cap i.e,.will be zero right(in waveform at t=0,Vout=0)..But why V/2..can u clear it.
@analogeasy-peasy75592 жыл бұрын
Can you please see the video named " Most Important RC Circuit Concept" in this channel itself.
@amitjana81722 жыл бұрын
For the voltage of a capacitor to jump we need infinite current. At t=0+ infinite amount of current flowing through the capacitors. Here the value of both the capacitor is same. If we apply voltage division rule of the capacitor then the voltage across each capacitor will be V/2 at t=0+.