The Fourier Operator - L18 - Frederic Schuller

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Frederic Schuller

Frederic Schuller

Күн бұрын

Пікірлер: 11
@active285
@active285 8 жыл бұрын
12:00 Typo: Facts (i) should read L^2(IR^d). In fact, it even holds: S(IR^d) c L^p(IR^n) für p≥1. 26:50 To be honest: Normally, there is no problem, since we usually define F[f](x) := \hat{f}(x), i.e. the hat does not meet the variable x in round brackets. Hence, \hat{f} can be understood as a shorthand for F[f]. Is the notation presented here maybe physicist notation?
@jwp4016
@jwp4016 7 жыл бұрын
Thanks! It seems worth to remark on your comment. Typo in your typo report : That last n should be d. :) For your second point, his notation has a distinctive value, as you can see at 44:40. To use the "hat(f)" notation, we should, for example, define a new function f'(x) := f(x-a), and then write it as hat(f')(p). But the "hat(f(x))" notation allows us to express it directly in terms of f and variables. Actually, we can fully be rigorous while sticking to variables. Extend our first order language to include lambda calculus. Then, formulas of the form f = λx.f(x) are a well-formed formula . Thus we are perfectly justified to use expressions like hat(λx.f(x-a)).
@stefaanmelis
@stefaanmelis 5 жыл бұрын
1:20:00 Herr Schuller was at some point somewhat confused, as he confessed himself. Therefore I believe he gave a wrong explanation why we get y^2 shifted by x into (y-x)^2. According to his explanation you have to arrange this by applying a binomial manipulation of (p^2+ipx). In my opinion, the position shift (y-x) after the Fourier operator is simply caused by the phase shift prior to applying the operator (according to the proposition that Herr Schuller showed earlier in the lecture).
@mbivert
@mbivert Жыл бұрын
Not sure this is exactly what you meant, but for future references, in the lectures notes (Simon Rea, Richie Dadhley), the change of variables is performed in two steps (z
@millerfour2071
@millerfour2071 3 жыл бұрын
21:21, 31:44, 1:13:27
@ndmath
@ndmath 5 жыл бұрын
Does anyone know a good resource for extra information on the Fourier operator as discussed here?
@ernestomamedaliev4253
@ernestomamedaliev4253 4 жыл бұрын
Its just Fourier analysis, there is a lot of bibliography around it. I studied it in spanish, so I dont know what book might be suitable for you. In any case, there are a lot of books that might be helpful, even if the information is too extense. For the use in QM, maybe you can find enough information in "Quantum Mechanics - Cohen-Tannoudji, Vol 1". You can get it through this link: www.zuj.edu.jo/download/quantum-mechanics-vol-1-cohen-tannoudji-pdf/ Look for the index somewhere, but the book is good in order to explain the mathematical stuff usually used when one deals with QM. Good luck!
@ernestomamedaliev4253
@ernestomamedaliev4253 4 жыл бұрын
PS: he just gave some theorems and results that you can easily find on wikipedia I guess.
@hassaannaeem4374
@hassaannaeem4374 2 жыл бұрын
48:03 cool, if true!
@jimnewton4534
@jimnewton4534 2 жыл бұрын
Schuller proved that the inverse Fourier transform of the Fourier transform of f is f. Is it necessary to show that the Fourier transform of the inverse Fourier transform of f is again f ? Because if you don't know they're inverses then you don't know they commute, right?
@mbivert
@mbivert Жыл бұрын
I think this is correct: we've proved in this lecture that F^{-1} is the left inverse of F; it remains to prove that F^{-1} is the right inverse of F. However, this likely has been omitted because the proofs are very symmetrical: with a similar regulator, executing the Fourier transform and its inverse, we're still able to shift limit and integrals with dominated convergence & Fubini.
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