Electric Field Due to a Charged Disk, Infinite Sheet of Charge, Parallel Plates - Physics Problems

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Thank you! Your video was the first to explain where "2πr dr" originates from. Obvious in hindsight but didn't make sense until you showed it!

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[@rajukc1077]

i like the integral part solved by you at charged disk...its difficult to find that in other lectures...saved my day.!!! thanks a lot

[@detectivebrown4499]

after integration why did he devided all on -1/2 thanks in advance

[@Spectrojamz]

@@detectivebrown4499 He didn't divide by -1/2. That value was gotten from the u sub. He only factored it out of the integral since its a constant

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[@nijatmehtiyev9698]

You are the best ! Only think i did not get , why Ey in the beginning equals to zero? Why we consider postive charge in top and bottom? Thank you for answer!)

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[@Festus2022]

You show the disk (and thus the infinite sheet) as having an area vector orthogonal to X. Does this matter? What if the disk area vector is parallel to X?

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Also it would be nice if you made videos other situations that does not involve finding the electric field at the center.

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[@palmoasis]

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[@dragojakimovski6018]

Sir thanks for the video but shouldn't the integral be from r to R

[@aryanshahu6167]

dr is what you integrate with respect to. When integrating, we go from radius of 0 to R (radius of disk).

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[@josephwoltering3785]

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[@cyrillemagdi7717]

You could have just multiplied the integral by half and put 2 in the numerator so you ´ll have the differential of what’s inside the bracket then you could add one to the exponent and divide the whole by the new exponent , you ´ll get the same result without the u-sub. method

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[@jesusmrosario-claudio4104]

Thank you once again

[@midispiache6774]

Does this reduce to the point charge formula when R approaches 0? It does not seem to work for me

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[@yahiabouchaala1195]

how do I know from where to where should I integrate in this example you integrated from 0 to R please I want to know that point!

[@stinbhavsar3089]

@Yahia Bouchaala We integrate when we take a really really small part of a whole using some assumptions and adding them by giving it limits In this example we want to find the electric field due to a disc of radius r so we would take a small part of the whole disc and give them limits So for the disc we would integrate it from 0 to r because we want to find the field bcoz of the whole disc Correct me if i m wrong as i m new to this topic too

[@yahiabouchaala1195]

@@stinbhavsar3089 thank you so much sir glad you answered my question and it was really helpful Thank you again

[@brookeolsson8001]

how do you get the electric field?? I thought E = kQ/r^2? Where does theta/2E(0) come from?

[@nijatmehtiyev9698]

that's physics buddy XD

[@nirmaljyotibiswas752]

That's Sigma (charge density) / 2 Epsilon Naught (Eo)

[@khaledsuleiman422]

are we need to show the proving how we deduce the equation in the exam or its not nessacery????

[@tiygar8548]

depends on your teacher ofc but probably you dont need to do it

[@JulienVIDS]

What is the difference between capital R and lower case r; are they both the radius?

[@rayxr]

Big R is the radius of the total disk. Lower case r is the radius of the inner disk.

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[@petermontgomery4597]

Why isn't Enet = 2 Ex

[@MarisaEsau]

why is sigma a constant, if sigma = Q/pi*r^2 and is dependent on r?

[@raiyanreza9764]

when do you know when to use U-sub vs Trig-sub?

[@ajn1881]

Typically for U substitution, you will have a function and its derivative in the integral. Like 2x/x^2, you could simplify this. but u= x^2 and du (the derivative of u) = 2x thus du/u.

[@mattthompson2385]

I understand how to find the field due to a disk, but how do you find the force due to a disk?

[@angelmehta5152]

Just multiply it with the point charge I guess? Because Electric field= force/charge

[@deepakjain6419]

Bro if this is conducting disk then ans is diff Or same

[@AlokSingh-jd4iv]

Thank you

[@Hardly_Human]

Why are you integrating from 0 to R in the first part. Shouldn't it be from 0 to 2pi because it is a full circle. I am not sure. Please help me understand. Thank you.

[@kingamv107]

Actually it is r=0 to r=R

[@eyramdiaba828]

Why is there a division by two when finding the Electric field produced by an infinite sheet of charge

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[@wahidhamidy6886]

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[@varunupadhyay1576]

what about if the sheet is conducting??

[@rayxr]

Th electric field would be the same.

[@joeb6225]

The field would be the same away from the conductor, but inside of the sheet, the field would be zero.

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17:07

[@Carmen-uo4zi]

Appreciate how you derived the formula for finding the electric field for a charged disk, but is it necessary?providing the formula and working directly with problems using the given formula is better unless your a physicist...

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thats the only reason this video is better than others because he takes the time to explain the concepts behind the formula.

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[@ujwaltayde7681]

Wait electric field due to a plane sheet of charge should be --------->surface charge density(sigma)/2×epsilon

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