Centripetal Acceleration & Force - Circular Motion, Banked Curves, Static Friction, Physics Problems

[@TheOrganicChemistryTutor]

Circular Motion - Free Formula Sheet: bit.ly/4gIUL3r Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections

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Timestamps for this lesson: Note: He sometimes teaches concepts(Kepler's third law, tangential acceleration...)during the practice problems so make sure to look out for those 0:00 - Intro 0:15 - Centripetal Force 14:31 - Centripetal Acceleration 15:22 - Period and Frequency 16:32 - Tangential Velocity 32:40 - Vertical Circle Problem(Varying centripetal acceleration) 1:10:59 - Gravity and Newton's Law of Gravitation Problems: 1. 18:50 2. 23:42 3. 26:27 4. 35:26 5. 38:05 6. 40:17 7. 46:31 8. 50:15 9. 58:12 10. 1:01:41 11. 1:07:31 12. 1:15:51 13. 1:22:29 14. 1:24:35 15. 1:31:22 16. 1:36:53 17. 1:43:24 18. 1:47:45 19. 1:50:34

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1:01:30 the answer for net acceleration is done right but due to intermediate rounding the answer became off by 0.4 In this scenario, 0.4 is a slightly large difference since the answer itself is less than 10. Rather if a direct input of the v^2/r in the Pythagorean equation then it would yield about 5.26. You taught the right way but it was just off due to rounding. But still you helped me learn how to approach these problems

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Slight correction for the teatherball problem, for T x all you use is mv^2/r and T y is mg so you get 29.6 and 2.45. By pathagorean T = 29.7N right?

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One thing that really helped me understand the free-body diagrams is that remember that fNET= Fac all the time. So in the roller coster example, at the bottom, Fnet= Fac= FN-mg and then at the top it is Fnet = Fac = mg - FN

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arham siddiqui what do you mean by fac? I guess i have studied too much and am starting to mix things up

[@arhamsiddiqui7083]

@@ro1882 i meant force of centripetal acceleration

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I'm just curious why the problem at 45:00 does not use formula FT = sqrt(FTx^2 + FTy^2), taking into account the effects of gravity

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35:21 I got a question. Shouldn't the forced acting on the ball at point A be T-Fg because only T is pointing towards the circle. Point C should be T+Fg because both T and Fg are providing the centripetal for, so they should both be positive

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it has been 5 years that u made this video. I am not sure whether u r gonna answer my question or not. But still, (56:39) u solved Normal Force equals to mg/cos. What makes it different from the other questions that the normal force was usually mg x cos? why makes the normal force to be mg/cos? Also, Thank you for making these videos. I like how u explain the general concept first and then u solved questions that are related to the concepts that u just taught.

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40:36 46:51 1:02:01 1:07:33 1:24:40

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Great video, but one question. At about 46:28 did you just not count the tension force for the Y component when calculating the overall tension force because the Y component tension is almost negligible? I counted the Y component and got 29.7 N instead of 29.6 N.

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8:49 in this example, I would think that the normal force is balanced by a force of the magnitude of mgcosΘ and in an opposite direction; while, the acceleration along the direction of the velocity is due to a net force equal to the (mgsinΘ-friction) force. At the initial point when the moving object is no longer in touch with the ground i.e. when the gravitational force is not balanced by the normal force, the object accelerates downwards by gravity.

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