Uniform Circular Motion Class 11

Uniform Circular Motion Class 11
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Uniform circular motion in physics refers to the motion of an object traveling in a circular path at a constant speed. Several key characteristics define uniform circular motion:
1. Constant Speed: In uniform circular motion, the object moves around the circle with a constant speed. This means that the magnitude of the object's velocity remains the same throughout its motion.
2. Circular Path: The object follows a circular trajectory, which means it travels along the circumference of a circle.
3. Centripetal Force: To maintain its circular path, the object must experience a centripetal force directed toward the center of the circle. This force is responsible for keeping the object from moving in a straight line and causing it to continuously change direction.
4. Tangential Velocity: Although the object's speed remains constant, its velocity is not constant in direction. The velocity vector is always tangent to the circle at the point where the object is located, and its direction changes as the object moves around the circle.
5. Angular Velocity: Uniform circular motion is often described in terms of angular velocity, denoted by the Greek letter omega (ω). Angular velocity represents the rate of change of angular displacement and is measured in radians per second (rad/s). The relationship between linear speed (v), radius (r), and angular velocity (ω) is given by v = ωr.
6. Period and Frequency: The time it takes for the object to complete one full revolution around the circle is called the period (T), while the number of revolutions per unit of time is referred to as the frequency (f). These are related by the equation f = 1/T.
Uniform circular motion is a fundamental concept in physics and can be found in various real-world scenarios, such as the motion of planets in their orbits, the rotation of wheels, and objects moving in circular tracks or roller coasters. Understanding uniform circular motion is essential for analyzing and predicting the behavior of objects undergoing this type of motion and for solving problems related to centripetal forces and accelerations.
In circular motion, there can be three types of acceleration involved:
1. Linear or Tangential Acceleration
2. Centripetal Acceleration
3. Angular Acceleration
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[@salmanshugriaden2916]

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[@NathanMuluken]

CSPS ?

[@KehaliGirumneh]

👍

[@AdityaSingh12325]

Answer - Linear Velocity = 2.199 m/s Centripetal Acceleration = 69.08 m/s²

[@vijaykumarverma6684]

I have already completed circular motion, but still came here to watch your interesting way of teaching , Lots of love Sir❤

[@ManochaAcademy]

Thanks! Great to hear you like the videos 🙂

[@shrekek]

the odds of it happening that i was just studying this chapter when you uploaded this! 😂 I've been following you since my 9th grade, and now I'm in 11th and preparing for jee!! Props to you, you are awesome, one day i would love to meet you when i reach college ❤

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[@ManochaAcademy]

We are uploading more videos of Class 11 :) Stay tuned ...

[@Abhishikth2025]

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[@cartoonic6039]

I have a very simple but question. Why doesnt the object collapse into the point. Since the centripetal force is an acceleration is increasing with time it should get to a point where its high enough to pull the object towards its centre. For example: The electron in an atom if not for its stationary state it should be pulled towards the nucleus since the proton and nucleus attract but what keeps it moving in a circular path is the fact that they have fixed energy called stationary States so they can't lose energy. But objects in the real world dont have fixed energy level so what keeps them in circular path? Another example is that if we change the mechanics occurring on the body interms of force, The centripetal force will be the F=m×a but converting the objects tangential velocity into force its F=0 since it has no acceleration.Resolving the 2 forces the object is supposed to move towards the center so why does it still move circular

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[@user-wu2rm3bh4y]

In a Uniform Circular Motion, the speed v remains constant. If the object makes n revolutions (cycles) in a time t, then it travels a distance s: s = 2 • 𝜋 • r • n and v = s / t = (2 • 𝜋 • r • n) / t Since v = ω • r, then ω • r = (2 • 𝜋 • r • n) / t. This implies that ω = (2 • 𝜋 • n) / t If ω = 2 • 𝜋 • f where f is the frequency, then 2 • 𝜋 • f = (2 • 𝜋 • n) / t. This implies that f = n / t where n is the number of revolutions, n is dimensionless, n has unit rev/rev. Since the period T = 1 / f, then T = t / n. Since the period T is the time it takes for the object to complete one revolution (one cycle), then the unit of T is: s/(rev/rev) equal to seconds per number of revolutions (second per number of cycles). Since the frequency f is the number of revolutions (cycles) per unit time (usually seconds), the unit of f is: (rev/rev)/s equals the number of revolutions (number of cycles) per second. The unit hertz (Hz) replaced the unit cycles per second, which is actually the number of cycles per second. Finally, it is understood that in the formula ω = 2 • 𝜋 • f the unit conversion is (rad/rad) = 2 • 𝜋 • (rev/rev). This confirms the unit of angular velocity ω which is (rad/rad)/s.

[@xyzgamer-re9qx]

thankyou so much for making it simpler to understand 🌸✨

[@suhlaing9423]

thank you sir. very clear explanation.

[@odokenneth3712]

Please sir what is the difference between circular uniform motion and periodic motion

[@truptimohanty9197]

Thank you So much sir for making physics videos of class 11

[@samriddhisharma3694]

Best video to understand this topic

[@arockiamsamayal4367]

Thankyou sir❤❤

[@delademnyamadi1270]

i am from Ghana i really love and appreciate your teaching 👏👏

[@TariqAziz-sb2st]

Linear velocity is 2.189 radian per second Centripetal acceleration is 690.17 radian per second square

[@user-wk1fx3wl5e]

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[@ManochaAcademy]

Great to hear that you liked the video. We will be uploading more Class 11 videos!

[@Arfatuddin1]

Does it rotational motion

[@user-es4ww3xg7h]

I really do appreciate your videos. Thanks a lot. My answer is v=7916.8

[@Lily20008]

Linear velocity=2.2 m/s Centripetal acceleration=6.9m/s^2 approx

[@netranandaswain2911]

Hi

[@netranandaswain2911]

Give me full slove answer

[@netranandaswain2911]

Please

[@noidea9289]

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[@dandarte4062]

Uniform circular motion has no acceleration. There is no linear vector(except in the imagination), therefore no centripetal acceleration or force. The only force acting on the coin is away from the centre and is called the centrifugal force, that at sufficient speed of the table, will cause the overcoming of stiction and then a complete change of mechanism occurs. There are centrifuges manufactured but no centripetal machine exists.

[@mainnahibataunga788]

Sir pls answer Is tungsten a conductor of electricity or insulator ?

[@LathaP-xg5my]

Conductor

[@i.must.work.]

it has very high resistivity but you still refer to it as conductor

[@pulkit1772]

LINEAR VELOCITY = 2.2m/s CENTRIPETAL ACCELERATION= 69.14m/s^2

[@user-sr4hn8tp1n]

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I am from Nigeria I really appreciate it sir

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Nice video, sir. Thank you so much, sir

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Beautiful

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Sir, I'm in 11th now. Could you please upload videos on your website for physics and chemistry (class 11)? Your physics videos helped me prepare for my boards in 10th. Now, I've also enrolled for the Python course. Love it ❤️

[@hariff6698]

I think v bar = omega ×r not r×omega ......is it right please check.....

[@Nonstoplofi.01]

Thank you sir

[@Zumii_]

Sir is this acedmy not make videos for bs students of physics

[@Palowrites123]

❤❤❤

[@Parachutes123]

Sir pls share the answer of the numerical with us....

[@debadritohalder478]

14:20

[@cschandu]

good

[@user-mq2fl3mq7w]

Good job sir

[@ManochaAcademy]

Thanks

[@farhanalrashid6655]

m = 5 kg Diameter = 14cm = 0.14m Radius =0.07m f = 300/60= 5hz v = rw = r x 2πf = 0.07x2x22/7x5 = 0.088m/s a = w²r=69.14 m/s²

[@devansh9798]

Linear velocity = 2.2m/s not 0.088m/s

[@dipteshkumarsahoo5503]

Itne confidence se galat answer kyun likha hai

[@rajeswarirella7710]

Linear velocity = 219.8 m/s Centripetal acceleration= 6901 m/s^2

[@rajeswarirella7710]

Sir am i correct or not

[@A.guy.with.HIV23]

I think centripetal acceleration is 6815

[@cartoonic6039]

Linear velocity is 4.4m/s

[@cartoonic6039]

1 rev = 2pie rads(2×3.142) 300rpm=(300×2×3.142)/60since me want to change minute to seconds. 300rpm=31.42rads/s Velocity = radius×angular vel. =7× 31.42 =219.94cm/s Or we change 14cm to m to get it in m 7cm=0.07m Velocity=0.07×31.42 =2.2m/s

[@cartoonic6039]

Centripetal acceleration will be 69.14m/s^2

[@shuaibjemil]

Thanks for this sir. Sir what differentiate circular motion from rotational motion?

[@LexusAdamMG]

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My fav youtube teacher

[@ManochaAcademy]

Thanks 😊

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One of the most underrated teacher in youtube 😢😢

[@FrankMe.]

Why suddenly 2pie radian becomes 2pie only where is radian in formula

[@ManochaAcademy]

Angle is dimension less quantity. Just a number.

[@TariqAziz-sb2st]

Appload more lecture plz

[@michaelyawkal4592]

Hello Sir Have Phisics question can I Send you

[@ROHIT-yi5dt]

Angular acceleration and tangential acceleration are both zero 24:52

[@ROHIT-yi5dt]

Why?

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1st😅

[@ManochaAcademy]

Thanks for watching!

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Sir i want to translate your words in Bengali please

[@sai_baba_1919]

Second

[@ManochaAcademy]

Thanks for watching so fast!

[@storyforkids22]

The answer for the question: Vt= 2.19 radm/sec and ac= 69.02 rad/sec2

[@johnikeh1861]

How

[@jangalasasank4658]

Here pie means 180 know sirr

[@ManochaAcademy]

Yes, Pi radians is 180 degrees

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Aa na pata chalega😊

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[@user-wu2rm3bh4y]

Many people wonder why radians do not appear when we have radians * meters. Here is an attempt at an explanation: Let s denote the length of an arc of a circle whose radius measures r. If the arc subtends an angle measuring β = n°, we can pose a rule of three: 360° _______ 2 • 𝜋 • r n° _______ s Then s = (n° / 360°) • 2 • 𝜋 • r If β = 180° (which means that n = 180), then s = (180° / 360°) • 2 • 𝜋 • r The units "degrees" cancel out and the result is s = (1 / 2) • 2 • 𝜋 • r that is, half of the circumference 2 • 𝜋 • r s = 𝜋 • r If the arc subtends an angle measuring β = θ rad, we can pose a rule of three: 2 • 𝜋 rad _______ 2 • 𝜋 • r θ rad _______ s Then s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r If β = 𝜋 rad (which means that θ = 𝜋), then s = (𝜋 rad / 2 • 𝜋 rad) • 2 • 𝜋 • r The units "radians" cancel out and the result is s = (1 / 2) • 2 • 𝜋 • r that is, half of the circumference 2 • 𝜋 • r s = 𝜋 • r If we take the formula with the angles measured in radians, we can simplify s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r s = θ • r where θ denotes the number of radians (it does not have the unit "rad"). θ = β / (1 rad) and θ is a dimensionless variable, and its unit is rad / rad. However, many consider θ to denote the measure of the angle and for the example believe that θ = 𝜋 rad and radians * meter results in meters. Mathematics and Physics textbooks state that s = θ • r and then θ = s / r It seems that this formula leads to the error of believing that 1 rad = 1 m / m and that the radian is a dimensionless derived unit as it appears in the International System of Units (SI). In the formula s = θ • r the variable θ is a dimensionless variable, it is a number without units, it is the number of radians. When confusing what θ represents in the formula, some mistakes are made in Physics in the units of certain quantities, such as angular speed. My guess is that actually the angular speed ω is not measured in rad / s but in (rad / rad) / s = 1 / s = s^(-1).