Thanks

Thank u sir

Thank you for your brief and clear explanation

These are great videos. Very clearly presented and everything is derived from first principles. I'm not sure why they don't have more views. Thanks

As you explain it is to describe LTI systems but we use this notation in time harmonic quantity, With the time harmonic quantity how phasor makes assumptions, pls explain

Mum help, am about to run mad

@ 3:29 So the yellow line on the circle is an area of the sphere! Hmm, why do I keep staring at these three buttons?

not exactly get the “simple circuit analysis”, as I understand, you use KVL, where you find the current looking from port 1: which is V1 divided by Z1 + Z2||(Z3+Z0), and from port 2: V2 divided by Z2||(Z3+Z0), and I have no idea, why do you multiply the right part of this 2:03 equation by Z0/(Z3+Z0)

very insightful

The most concise yet thorough explanation. Somebody was real busy during pandemic! Thanks for the great work you did!

phenomenal. thank you.

I’m reading Pozar. This series is gold.

I'm studying a master's degree in electromagnetic fundamentals, my difficulty is the equations, I would have more classes with the fourier transform and z transform

Wonderful video! Nicely explained and easy to understand. Keep it up!

0:27 hogwash. the previous graphic labeled the blue vectors as the magnetic field, now you're claiming this is somehow another electric field? even if that were the case, it wouldn't create nor explain a circular wave.

I never can get a reflector to work with the antenna I have built....no matter the spacing. The signal level always drops with a reflector.

@4:08 the plot shows the "dipole length in wavelengths" (l/lambda). Does this mean that this chart is independent of the actual nominal wavelength? While the term k*l can be expressed as 2*pi*(l/lambda), I'm having trouble how to reformulate the term (2*k*a^2)/l in Xin without having to pull out a nominal value for lambda e.g. (2*pi)/((l/lambda)* lambda^2).

I miss links to right playlist.

@ 2:56 With a target-frequency of 5 GHz the wavelength is 0.06 m. Thus, the half-wave dipole antenna is only 3 cm. long. en.wikipedia.org/wiki/Dipole_antenna#/media/File:Half_%E2%80%93_Wave_Dipole.jpg

That was a nice, no nonsense treatment of (a part of) the subject. And well presented too. Thanks.

I have A QUESTION: If for a single-frequency signal the velocity of propagation v = 1 /(L.C)^1/2, then it seems to me that v is entirely determined by components of the lossless transmission line (L and C). So I wonder where the refractive-index of the medium between the wires comes into the picture?

日本にはもっと素晴らしい発明がたくさん有る🇯🇵万歳

Love to see the concise mathematical derivation that most videos would skip 👍

@ 0:07 If the AC-frequency is 60 Hz, then the wavelength is 5 million meter. The wires in your house are thus electrically very small compared to this wavelength.

Excellent! Thank you.

this series really helping me out. THANKS!!!

<3<3<3

Small remark: mu_0 is no longer equal to 4 pi 10^-7 H/m, it changed in 2019 to 1.25663706212(19)×10−6 H/m as part of the redefinition of the SI units.

Best lecture mam eyes are very beautiful

Great explanation, young lady. Thanks a Million!

You explain to me in five minutes what it took my professor a whole semester

You are awesome

Hi, I am not able to see the option of Assign boundry--> Master in HFSS 2024. Can you kindly let me know how to handle this in HFSS 2024

Why TEM is the dominant mode for Coaxial t.l

can you help me to make antenna work from 10ghz to 15ghz pls.

please correct the mistakes in formula , instead of Z1 its shown Z0 (@1:12)

Why?

Big Aha moment. The single charge position derivatives of subsequent orders never vanishing for sinusoïdal functions really nailed it for me. Awesome explanation. Thanks a bunch.

Looks like quantum physics to me.

you are the best thanks a lot

What is "C" in "R_r"?

Does the charge concentrate at the ends or uniformly over the polar length?

thanks so much fren, I am watching this playlist in 2024 and i am understanding everything about transmission lines and impedance matching! i am from kenya!

💛

Thank You KLS

Tq u

I love you

U explain beautifully. Ur channel is underrated!

IN GENERAL, A CAPACITOR CAN HAVE A VOLTAGE-DROP TOO. BUT AT HIGH FREQUENCIES IT GOES TO ZERO. I SUPPOSE THAT THE CONDUCTANCE IS JUST ASSUMED TO BE NEGLIGIBLE.

Thank you for the Great Video.