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3ds Max Tutorial - Slider-crank mechanism Part 2

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Lee Minardi

Lee Minardi

Күн бұрын

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@Team_rk288
@Team_rk288 Жыл бұрын
CORRECTION. My post #2 does not show the unit vector for the variable ZDown. Here are the complete set of expressions. LBEnd = PtLongEnd*BoomLong*dumBase SBEnd = PtShortEnd*BoomShort*dumBase L1 = length(LBEnd.row4-SBEnd.row4) LT = 250+CableLen ZDown = (matrix3 [1,0,0] [0,1,0] [0,0, 1] [0,0,L1-LT]) LBEnd*ZDown lee.Minardi can you help me plz do a tutorial of this mechanism also i want to a hose with that crane operating end thanku
@beamyjinn6996
@beamyjinn6996 7 жыл бұрын
In case anyone else's crank has a 90° offset too: it's alpha+pi/2 for you in the expression instead of just alpha. Or alpha-pi/2 depending on the direction. :)
@3dvovk
@3dvovk 6 жыл бұрын
Awesome! Thank you.
@borzacch
@borzacch 7 жыл бұрын
Thank you. But it could be done with IKSpline Solver much easier
@LeeMinardi
@LeeMinardi 7 жыл бұрын
My goal here was to provide an example of how expression controllers are used and to provide an exact solution for crank-piston rigging that can be moved into any orientation. I am interested in seeing how you would use an IK Spline solver. Can you provide a link to a tutorial? Thank you, Lee
@borzacch
@borzacch 7 жыл бұрын
and some tasks where only expressions and scripts can be used vk.com/videos1050874?z=video1050874_171558014%2Fpl_1050874_-2
@3dvovk
@3dvovk 6 жыл бұрын
Привет. Так и не нашел, как может IK Slover решить прямо эту кинематическую задачу (так-чтобы в соответствии с вращением кривошипа, правильно двигался поршень), обратная - да, легко, когда двигается поршень и в соответствии с этим вращает кривошип.
@LeeMinardi
@LeeMinardi 6 жыл бұрын
@@3dvovk You state (via google translate) "Hey. I didn’t find how IK Solver can solve this kinematic problem directly (so that, in accordance with the rotation of the crank, the piston correctly moved), the reverse is yes, it is easy when the piston moves and in accordance with this rotates the crank." Exactly! That is why I used the method I did because I wanted an exact solution and an IK Spline based "solution" does not do that. Yes, of course, moving the piston and having the crank follow is easy (until the mechanism gets to the crossover point).
@beamyjinn6996
@beamyjinn6996 7 жыл бұрын
Thank you very much for this tutorial! Almost gave up on doing this in max. However, I ran into a problem: I want to create an engine with two cylinders, so I need it to work in both directions. But it only works nicely with the crank being on the left side as shown in the video. I guess I have to change the expression to match the change of dirction but I don't quite know how. Just adding an offset won't do it because the rod won't connect properly to the cylinder: imgur.com/a/TxG4n
@LeeMinardi
@LeeMinardi 7 жыл бұрын
Assuming the 2nd piston is to the left of the crank (and mirrored), and that it has the same rod length as the first piston, the expression for the 2nd piston will be the same as for the first piston except there should be a - instead of a + in front of the sqrt term. That is: xpos+crank*sin(radToDeg(alpha)) -sqrt(rod^2- (h+crank*cos(radToDeg(alpha)))^2) If the rod length is different then change the value of rod accordingly for the piston2 expression controller.
@LeeMinardi
@LeeMinardi 7 жыл бұрын
I don't know why sqrt(rod is crossed out in my last comment but the expression should just show a - in fron of sqrt xpos + crank*sin(radToDeg(alpha)) - sqrt(rod^2- (h+crank*cos(radToDeg(alpha)))^2)
@beamyjinn6996
@beamyjinn6996 7 жыл бұрын
Ha, I knew I just had to put a - somewhere. Works lika a charm, thanks again!
@borzacch
@borzacch 7 жыл бұрын
Try tu use IKSpline Solver. it works perfect in any direction and angle.
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