@@TechnicalBytes Let overflow byte (1024 + n) Bytes written = 1024 + n Bytes read = n Writing time < reading time (1024 + n)*25 < n*80 => n =466 Hence 1024 + 466 = 1490
@TechnicalBytes2 жыл бұрын
@@ShailendraKumar-uk8bm great 👍
@realitycheck....9704Ай бұрын
thank you sir
@TechnicalBytesАй бұрын
Most welcome
@AbhishekSingh-up4rv2 жыл бұрын
Thank You
@TechnicalBytes2 жыл бұрын
You're welcome
@rahulgoyal79292 жыл бұрын
Very nice 👍👍👍👍👍👍
@TechnicalBytes2 жыл бұрын
Many many thanks
@sanyamsaumay702 жыл бұрын
Good sir
@TechnicalBytes Жыл бұрын
Thanks and welcome!!
@bhagatsingh34312 жыл бұрын
Nice video please share answer also sir
@TechnicalBytes2 жыл бұрын
try to think .. dear !!
@idontcare-tk1te2 жыл бұрын
I don;t understand what duty cycle means/implies with respect to read, write enables
@TechnicalBytes2 жыл бұрын
duty cycle = Ton/(Ton+Toff) right? Duty cycle in percentage = Ton/(Ton+Toff) * 100 write enable duty cycle = 50%, it means Ton/(Ton+Toff) *100 = 50 Ton/(Ton+Toff) = 1/2 2xTon = Ton + Toff Ton = Toff which means Ton is equal to Toff i.e. for one clock cycle wr_en is high and for one clock cycle wr_en is low. In short duty cycle tells the ON time as per the percentage of total time. For read enable, duty cycle is 25% Now, without calculating you can tell that for one clock cycle read enable is high and for 3 clock cycles remains 0. Let me know if you need any further clarification.
@idontcare-tk1te2 жыл бұрын
@@TechnicalBytes okay, I think I understand it now. The Toff period tells how many idle cycles are there between each read/write enables, right?
@TechnicalBytes2 жыл бұрын
correct, now try to calculate its answer!!
@preeti121212 жыл бұрын
321st byte ???
@TechnicalBytes2 жыл бұрын
how come? dear 321 is a wrong answer. I have a 1024 byte location FIFO .. So, it can easily absorb 1024 bytes .. correct answer will be more than 1024 bytes .. try to think .. I appreciate that you are trying.
@preeti121212 жыл бұрын
@@TechnicalBytes i m confused :\
@TechnicalBytes2 жыл бұрын
@@preeti12121 I will give its answer in the next video
@TechnicalBytes2 жыл бұрын
@@preeti12121 you can try the same question by consider write clock period 50ns and read clock cycle as 100ns
@meenugarg11022 жыл бұрын
Please do share answer sir
@TechnicalBytes2 жыл бұрын
I share its answer in the next video !!
@gauravkaushal73412 жыл бұрын
@@TechnicalBytes when will the video come?
@gauravkaushal73412 жыл бұрын
@@TechnicalBytes when will the video come?
@mihirshah56142 жыл бұрын
1490
@mihirshah56142 жыл бұрын
If the fifo depth is 1024, it will go full after around 37.24 us of continuous operation(1024*10^-6/(40-12.5)) and at that time write side would be writing (37.24*10^-6/25*10^-9) i.e. 1490th data byte