Your lecture is clear to understand, not too complicated that everyone can follow and fun, it's so helpful and enjoyable. Thanks!!
@alecadanglao83865 жыл бұрын
Top notch dude really needed this refresher cuz i got exams in 3 hours T^T
@JordanEdmundsEECS5 жыл бұрын
Hahaha I hope that went well xD
@rajgandhi40425 жыл бұрын
at 1:22 you mention boron atom give up their electron but how it has one e less than si.. Plz guide us
@JordanEdmundsEECS5 жыл бұрын
I definitely misspoke, thanks for finding that! Boron atoms will accept electrons and become negatively charged, phosphorus ions give up their electrons and become positively charged.
@apiyopao45865 жыл бұрын
At 1:23 I think u made a mistake you should have said boron ions accept electrons instead of saying give up electrons and become negatively charged That's why boron is called acceptor impurity as it's trivalent. After all if an atom gives up electrons it will become positively charged ion and not negatively chraged ion
@JordanEdmundsEECS5 жыл бұрын
You are absolutely correct, my mistake. Thanks for pointing it out!
@shahrukh35313 жыл бұрын
Learning from India 🇮🇳
@abdolw36825 жыл бұрын
Thank you very much, you are life saver, so much hearts ♥️
@johnnyromano50312 ай бұрын
Hi thank u for this lecture, it's so helpful but i did'nt understand why when we are in depletion mode (so we apply a positive voltage < Vth) holes come out in Metal and they lie on the surface between M and O or the position doesn't matter?
@reageno.7644 жыл бұрын
when we are applying a positive or negative voltage, is it moving Ec,Ei, and Ev bands or is it moving the fermi level?
@JordanEdmundsEECS4 жыл бұрын
Great question, you're exactly correct. If you apply the voltage to the capacitor, after everything settles there is no current flowing, so the fermi level must be constant everywhere (this is the definition of the fermi level). It's Ec, Ev, and Ei that bend to accommodate the voltage.
@mouwaten1003 жыл бұрын
a positive voltage at the gate attracts negatively charged ions at the other side, but those boron ions are already bounding with Si atoms. So when they move up they bring with them their silicon partner atomes, correct?
@komalsrivastava9734 жыл бұрын
How negative voltage applied on the semiconductor is going to drag the band diagram up? Please explain! Thanks!
@JordanEdmundsEECS4 жыл бұрын
This is a common confusion, band diagrams are the *electron* energy, so there’s a negative sign in the potential energy because the electron has negative charge (-q*V).
@iteshbharti85605 жыл бұрын
which book should I follow for MOS ?
@JordanEdmundsEECS5 жыл бұрын
Neamen is my personal favorite and very comprehensive.
@rajgandhi40425 жыл бұрын
At 6:56 you mention Ef is constant what that means 1)it can't move in band diagram of 2) bending of Ef will not take place?
@JordanEdmundsEECS5 жыл бұрын
Exactly. EF is constant means that it is the same value throughout the entire band diagram. This will always be true if the system is in equilibrium. Bending of EF does not happen in equilibrium. It will only happen when you have current flowing, and even then it gets kinda complicated (in the form of quasi-Fermi levels).
@rajgandhi40425 жыл бұрын
@@JordanEdmundsEECS when we apply positive voltage to gate after undoing the intrinsic band banding, Ef of metal should move down and Ef of semiconductor remains at the same place. Is it what you want to say?
@divya47526 жыл бұрын
Please make videos on mos amplifier
@JordanEdmundsEECS6 жыл бұрын
Videos on this should be coming in the next few days :)
@ThePreppar5 жыл бұрын
Very good, but not 'scaring away' but like charger repell each other :)
@gersh13325 жыл бұрын
Video is broken at 720p60 - video feed stops but sound keeps going.