Why charges reside on surface of conductors | Electrostatic potential & capacitance | Khan Academy

[@gouravmishra111]

these videos really create an impact in developing our concepts in physics...

[@Lets_crack_it0806]

yesterday I was asking to my sis this question and today u uploaded this video. I m shocked. love u❤

[@The--V]

@Dolananda Mokkapati 🤣

[@yuvrajtiwarybitmesraece7511]

Hats off to you sir well explained👍👍👌👌

[@seemafalak8334]

Ram Sir, shouldn't the charges be present on the inner surface as far apart from each other rather than being completely outside the metallic ring ? How do we get the excess charge on the outside?

[@taniwha5441]

Nicely explained and I like how excited you sound

[@Ultimatemaster_026]

Amazing explanation

[@TheElectromagno]

Good lesson

[@hoschi49]

I think the explanation with Gauß is wrong because the E field in Gauß is from the inner Charges only. Its Not the Total electric field. For the Total field you should add the field coming from the outer Ring Charges. The Total field at a point should be Zero but the E field in Gauß law is NOT the Total field. Thats my point.

[@samrinakhtar2006]

Actually it's not wrong.. According to gauss's law the electric field is due to all the charges,both inside and outside of the surface. But the term q on the right side of gauss's law represents only the total charge inside the surface.

[@jacclawrence2951]

you’re so good at explaining

[@FearlessS21]

Please upload nuclei full chapter.

[@sivam6949]

Thank you

[@vivekgupta3692]

Thank You Sir....😍

[@om-physicsnmvs]

Superb sir. 🙏Thank you

[@jameslimary755]

Do we agree that this is only valid assuming all moving charges have the same sign? Else I'm missing something out)

[@mihreteabgirma6351]

Thank you bro

[@pascale1411]

Thank you for the wonderful explanation! :D

[@jeonsday]

in the second case shouldn't the metallic surface right outside the cavity act like a shield? which would make it seem like no charge is enclosed by the metal

[@Puh539]

awesome

[@yash1152]

8:10 "but what if it wasnt a uniform surface" - ohh yes, i read in the introductory material, that in those cases, the charge distribution is inversely proportion to radius. am i right?

[@takhellambamkritibala3840]

Yes, you are .👍

[@weirdo5275]

It depends on the charge distribution imo but yeah that makes sense for most cases irl

[@jesussaquin6266]

is it because the electric field lines entering the object are the same leaving the object?

[@davidwoek3041]

Useful, thanks!

[@ayshaazath4240]

Thanks alot sir.what a great explanation

[@hassanjafari8318]

At the beginning of the video you are saying that positive charges start moving... This is a contradiction which we all know positive charges do not move. May you explain it to us please?

[@Abishangar]

Electron from a neutral atom outside the condensed charged area will leave from that atom and move to the side where the positive charge is condensed. So now a positive atom from that condensed area will be neutralized while the atom which donate that electron becomes positively charged. So apparently, the positive charge is moved!

[@pdfgovardhanb8093]

nice

[@carolinerozario9702]

1st view, like

[@thecreativecogent1215]

❤

[@mohdahmad8896]

2nd view

[@powerpatel704]

Gauss sir

[@Nimmavahini]

❤️