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A tough task in number theory at the USE in mathematics (No. 19). Decide, look, study, ask questions!
TASK TO ALL VIDEOS: wall-135395111_8104
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PAY ATTENTION: in the video I say a lot about the fact that the 11th, 13th and 17th numbers are simple, it’s true, but the main thing is that they are mutually simple with any others from the set. Let's say the number 7 is prime, but that does not mean that the greatest common divisor of seven and any other number is equal to one. Here is a simple counterexample: GCD (7; 14) = 7.
The current task will not be easy: three points after all, which means composite. But there will be something simple in its composition. Not complexity, of course, rather numbers. In general, success!
Condition. In a circle, in a certain order, once written numbers from 9 to 18. For each of ten pairs of neighboring numbers found their greatest common divisor.
a) Could it be that all the largest common divisors are equal to 1?
b) Could it be that all the largest common divisors are pairwise distinct?
c) What is the greatest number of pairwise distinct greatest common divisors that could result?
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