A Nice Olympiads Trick | No Calculator Allowed | 2^15 + 2^12 + 2^9 + 2^6 + 2^3 |

[@vikasheda2091]

Arrange it in increasing figures Then take comman 2^3 in each sequence

[@jimwalshonline9346]

Well done...I plan to save and study this one.

[@jerrypaquette5470]

I did it much easier. know your powers of 2's at least to 2^10 2^3 = 8, 2^6 =64, 2^9=512 2^10 = 1024 2^12 = 2^10 x 2^2 = 1024 x 4 = 4096 2^15 = 2^10 x 2^5 = 1024 x 32 = 32768 32768 +4096+512+64+8 = 37448

[@Guidussify]

What is the advantage of doing the calculation this very long way instead of just calculating powers of 8 (2^3) and adding them?

[@RyanLewis-Johnson-wq6xs]

I did it in my head.

[@RyanLewis-Johnson-wq6xs]

2^15+2^12+2^9+2^6+2^3=37448

[@yvesdelombaerde5909]

On met 2^3 en évidence, on a 8*(2^12+2^9+2^6+2^3+1) ensuite on recommence 8*(8*(2^9+2^6+2^3+1)+1) etc. Tous ceux qui ont appris à programmer sur les calculettes HP auront trouvé rapidement.

[@allentracht7821]

Learn and use the sum of a geometric series formula: en.wikipedia.org/wiki/Geometric_series#Sum