Electrical Engineering: Ch 13: 3 Phase Circuit (34 of 53) Average Power per Phase?

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Michel van Biezen

Күн бұрын

Пікірлер: 38

@Jnglfvr 4 жыл бұрын

Your formula in 3:13 should have the complex conjugate of the impedance in the denominator. S = V^2/Z*.

@karthik_xb 28 күн бұрын

yes

@kannanr9016 5 жыл бұрын

Thank you so much sir. One doubt sir, (line voltage is =square root of 3 × Vp ×angle 30°) the angle 30° is missing sir....

@maheekhan1075 3 жыл бұрын

Professor, in 3:10 , it should be Z* than Z.

@muhammadyunus9381 4 жыл бұрын

Sir but in Y delta 3phase circuit which u said its the common, both the linecurrent=√3Iphase and linevoltage=√3phase voltage then would the total powe of Y-Delta circuit be P=VLILcosΦ ?

@DarknessPr0w 4 жыл бұрын

The exact reason why i came back to this video. by all means please correct me if i'm wrong, but since we are only looking at the load in this stage. if you would draw a Y or delta load with the outgoing wires, not connected to any source. And deem the voltage between te lines the linevoltage, you will be able to see that in a delta circuit, the line voltage equals the phase voltaqge ( the voltage over the impedance), and the the linecurrent will be a facter sqrt(3) more than the current through the phase ( through the impedance). You will find the reverse being true for a y connected load. For me the confusing thing was looking at the possible source connections, for definitions of phase and line voltage. But once you look at the load it becomes alot clearer, hope this helps

@guloguloguy 2 ай бұрын

WOW!!!!!!! THANK YOU, VERY MUCH, FOR YOUR MOST EXCELLENT REVIEW OF THESE RELATIONSHIP FORMULAS!!!! MUCH APPRECIATED!!!!!!!

@MATHBOSS287 3 ай бұрын

in the rule S=Z times the magnitude of current ^2 you didnt mention of its the line current or the phase current which one is it?

@Goku2005whaa 3 ай бұрын

thanks you sir, what is the diff between Pp and normal P

@ricogarcia9341 2 жыл бұрын

Sir, I do recommend the proper usage of the terms complex power and apparent power.

@MichelvanBiezen 2 жыл бұрын

Feel free to add any comment.

@jonayedmohiuddin538 Жыл бұрын

yeah you are right

@MATHBOSS287 3 ай бұрын

@@MichelvanBiezen in the rule S=Z times the magnitude of current ^2 you didnt mention of its the line current or the phase current which one is it?

@udaykulkarni8989 8 ай бұрын

Nice explanation, Thank you very much

@MichelvanBiezen 8 ай бұрын

You are welcome

@ΚλέαρχοςΤσίγκρος-η5κ 10 ай бұрын

why u say that n a delta connected load vl = vp we learned that in a y-delta connection is vl = sqrt3vp with phasor 30 and il = ipsqrt3phasor -30

@lalembahmanahsatyaalmahabb8826 Жыл бұрын

Why dont you multiple the line voltage with 3 for total power?

@MichelvanBiezen Жыл бұрын

Just like with any RCL circuit, the power generated on each element (resitance, inductanve, capacitance) it will be out of phase. When you add the voltage drops across each element, it will always be higher than the total input voltage, but when you account for the phase difference they will add up correctly. Here with a 3-phase circuit you cannot add them up algebraically because of the phase difference.

@lalembahmanahsatyaalmahabb8826 Жыл бұрын

@@MichelvanBiezen thank you for your explanation, sir!

@saeedupdate8311 3 жыл бұрын

I think you forgot to say about the differences in phase voltage and line voltage angle. phase voltage will lag line voltage by 30 degrees (or pi/6 radian).

@Zuwwar 3 жыл бұрын

Hi. Shouldn't you have a Z* there?

@surendrakverma555 2 жыл бұрын

Very good lecture Sir. Thanks 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

@MichelvanBiezen 2 жыл бұрын

Thank you. Glad you found our videos.

@jacksparrow9532 Жыл бұрын

Hello sir. Thank you very much for the explanation. I'm currently confusing wether we need different formula for delta or star connection. Regards

@MichelvanBiezen Жыл бұрын

The general equation for the average power per phase is as shown in the video. The impendance of the circuit needs to be calculated as shown in the previous videos depending on the type of circuit you are dealing with.