An introductory example problem determining velocities and accelerations of masses connected together by a pulley system.
Пікірлер: 72
@ericaleonardi57764 жыл бұрын
i love this guy's intro. It actually makes me want to study structures hahaha just to hear it
@SeanDaNerd7 жыл бұрын
This was excellent. Setting up the datum and equations before solving has been tricky for me and my professor's tutelage just wasn't getting through. Thank you.
@stephanosphilippou13007 жыл бұрын
When it comes to education i am very picky. I just have to say that you're one of thebest out there. Thanks a lot for the time you have taken to prepare this and i hope to see you cover more topics related to mech.eng .
@troyjones37157 жыл бұрын
You sir are a champion and you deserve a bigger platform...
@robinc50834 жыл бұрын
Well explained! Sure you're helping a lot of desperate students! Thank you!
@jasonegay74476 ай бұрын
You've really helped clear up this concept of pulleys for me. Thanks a ton!!!!
@pinkcherry118 жыл бұрын
You are amazing! I already loved dynamics but you make it so approachable and fun!!! thanks :)
@meedo6137 жыл бұрын
that energy man :) Thank you for this example
@czeckeredcat6 жыл бұрын
LOL'd at the abrupt cutoff at the end: "Structure FRRR!"
@masooncap97692 жыл бұрын
you teach this so much better than my professor, thank you
@IQ-rl2wx4 жыл бұрын
These videos helped me a lot through university
@NaimishBaranwal6 жыл бұрын
excellent man!!! one question clear all doubts.
@project-moe7 жыл бұрын
literal beautiful video, subscribed
@juni1727 жыл бұрын
very well explained, thank you!
@nicenow258 жыл бұрын
That's what we need msn enthusiastic teachers!!!
@droppinhammerz8 жыл бұрын
this was really helpful! thanks!!
@deekaye57354 ай бұрын
thank youuuu verry muchh. this answers my questionsss i love this
@arunavamajumder68236 жыл бұрын
Thanks man. That was awesome
@aliangori8 жыл бұрын
You are a great tutor
@user-yg8ml8vu2x7 жыл бұрын
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@nbolt7510 ай бұрын
Thanks for the help !
@EpicPlayer9542 жыл бұрын
Crystal clear I can't thank you enough
@structurefree2 жыл бұрын
Thank you!
@fiveguysmenifee15133 жыл бұрын
Great content!
@oscarrinn4 жыл бұрын
I was a little confused about the equation that was derived for the second cable but then I remembered that what was outlined in red would be treated as a constant and we could exclude it.
@ing.erickosorio28874 жыл бұрын
Hi Oscar, if you don't have the answer yet. What's going on it's that's he's defining constant lengths and variable lengths, if you think about it, in reality the cables will stretch but that only means that certain parts as far as lengths is concerned will be the same and some will change length, but that's all based on the reference lines the has established. Now the red part of the cable your talking about will remain the same length no matter what, that's why it's taken as constant, since that cable is attached to 2 fixed points. I hope that helps.
@symbionictitan40743 жыл бұрын
life saver, Subscribed.
@comicstwisted6 жыл бұрын
Great explanation
@austinbeckd4 жыл бұрын
That was actually very clear and informative.
@danishphysics97697 жыл бұрын
what is the acceleration of two masses block when their are two pulleys and two strings.one string is connect to the one pulley and this one pulley on the inclined plane
@AloneGalaxy888 жыл бұрын
Thanks man :)
@irvinrayados938 жыл бұрын
Wich program do you use ? Excelent videos !
@structurefree8 жыл бұрын
i use camtasia
@RECrush16 Жыл бұрын
how could sm is changing length if the motor and the pully next to it are fixed?
@structurefree Жыл бұрын
The point m on the rope represents the motor
@paulotago86033 жыл бұрын
Quality mate.
@noreaction14 жыл бұрын
How does changing the angle of the incoming rope and outgoing rope at one pulley change the tension of the rope at that pulley? For example if the angle is 270 did not degrees as opposed to 360 degrees how does that change the tension? What if the angle is 180 degree as opposed to 360 degrees?
@halehallamehhaery18038 жыл бұрын
Hi, distance between pulley and the motor on the ground is fixed why you considered S_M?
@vegamario75436 жыл бұрын
thank you kind sir
@batterflyfury8 жыл бұрын
thanks very much. ^_^
@danese16362 жыл бұрын
Fucking hell man... I wish I watched this video when I was taking Mechanical Dynamics 3 semesters ago D: Excellent video!
@smtghosh6192 жыл бұрын
This was really helpful ❤️❤️
@structurefree2 жыл бұрын
So glad it still helps!
@mba2ceo5 жыл бұрын
Genius !!! VERY well explained !!!
@structurefree5 жыл бұрын
You are too kind!
@mba2ceo5 жыл бұрын
@@structurefree the only thing I would change the MOTOR reference before the redirect for symmetry :)
@faiyadking2932 Жыл бұрын
How did u get 2Sb for the second equation?
@l.rosemcsherry76216 жыл бұрын
do you not count the cable lengths that are above the datum? like the pi(r) of the pulleys that are used for the datum?
@structurefree6 жыл бұрын
I try to think of calculating the cable length from particle to particle. Some of those segments above the length are constant so they get lumped in to the constant.
@BrazitodeWawa8 жыл бұрын
what's up with them structural dynamics videos? you only recorded the easy part..
@MsMizlicious7 жыл бұрын
what about the distance on the right side of point M? Since M moves, that distance would have to change
@project-moe7 жыл бұрын
M is a variable, kinda like how u set "some distance x away", so it is accounted for
@mustafahasan65493 жыл бұрын
I am confused, shouldnt the length of rope between the pulley and the motor be constant? why did you denote it as Sm?
@shoukry84138 жыл бұрын
thanks man
@structurefree8 жыл бұрын
+Tarek Shoukry you're welcome!
@ryujinryuk6 жыл бұрын
i dont understand why u consider sm while its indeed constant . can someone explain ?
@Rycamcam4 жыл бұрын
I thought the same thing. The Sm length is constant -- the pulley and motor are both attached to the ground, thus stationary, thus constant. It's a constant, he just made a mistake
@matildaho5816 жыл бұрын
thanks homie this was actually mad helpful :) :) hopefully it was helpful enough so that I dont fail out of engineering school rofl lol :|
@Chloholio3 жыл бұрын
lol the inflection in your voice sounds like Sal Khan
@annrufino46946 жыл бұрын
lodi..tanx
@hjalmarschacht25596 жыл бұрын
Great example and an excellent description of the solution. Well done! Oh ... curb your enthusiasm. It may be cathcy.
@Patar1417 жыл бұрын
The distance between the motor and bottom pulley are constant, I assume they are fixed. So how can you say s_m changes in distance? The distance will always be the same, so it would be treated as a constant.
@kuenlai97366 жыл бұрын
Late reply, but you still need a point for the motor to add into the length equation with Sb.
@Iscrnd5 жыл бұрын
It is not a constant because he chose the reference of point M instead of the motor, and since point m is a point on the cable, and the cable is moving, point m is not a constant. Had he chosen Sm as a reference to the actual motor, you would be correct, but he chose a point on the cable instead which allows him to consider it as not constant
@salsamancer5 жыл бұрын
Just ignore the motor and imagine that the point M is being held by somebody and being pulled. It's the same thing in concept.
@ellyvatedaf3 жыл бұрын
LEARNEHHH
@nomad87236 жыл бұрын
thuglyfe
@andrewbudiman13107 жыл бұрын
definitely puesdo physics, alot of bookkeeping and less problem solving
@emery55815 жыл бұрын
I agree, good way of putting it. I just posted my opinion on this "presentation", look it up among the replies.
@ShiyaRam87406 жыл бұрын
Bakwas
@emery55815 жыл бұрын
This is not quite on an undergraduate level. Grade twelve, I would think. And even at that, you over complicate the solution. I tend to agree with the opinion of one of the commentators, "too much bookkeeping not enough physics". Teaching physics is about recognizing principles and getting solutions efficiently, not by "here you go, do this , do that, substitute here and there, use this formula or that formula".... This problem of the pulleys can be solved in one's mind without actually writing anything, the following is a guide: A downward shift in position in either of the moving pulleys will require an extra feed of rope length double the change in position. This is obvious at first sight. Therefore block A displacement is half of block B displacement which is half of the motor feed. Therefore the displacement ratio is 4 at block A, 2 at block B, with respect to motor feed.. Now, taking derivatives will maintain this ratio of the displacement maps, whatever they might be, so the rest of the problem is also pretty obvious. One more thing, if block A should weigh more than twice than block B, the system could not function....so, unless you place the proper restriction on the weights, you can not solve.